Answer:
Force on the proton will be 
Explanation:
We have given speed of proton is 20.3% of speed of light
Speed of light 
So speed of proton 
Magnetic field B = 0.00629 T
Charge on proton 
Angle between velocity and magnetic field 
Force on the proton is equal to 
This seems like a calculus problem. I'm assuming you would use cos and sin. so here's the vertical component +10.0m/s multiplied by sin60 = 8.66 rounded to the hundreths place. Now for horizontal, that would be +10.0m/s multiplied by cos60 = 5. hope this helped.
Answer:
Explanation:
solve the parallel resistances
30||40 and 50||30
17.14285714 and 18.75
total Resistance = 35.89285714
V = IR
9V = I *35.89285714
9V / 35.89285714 = I
0.250746 = I
Now use the resistance across AB
V = 17.14285714 * 0.250746
V = 4.29850
this is the Voltage drop across AB :P