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zavuch27 [327]
3 years ago
6

5. Electromagnetic radiation travels at a speed of 3.0 x 10^8 m/s.

Physics
1 answer:
creativ13 [48]3 years ago
6 0

Answer:

i think its b

Explanation:

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A 5.7 kg block attached to a spring executes simple harmonic motion on a frictionless horizontal surface. At time t = 0s, the bl
Genrish500 [490]

Answer:

Explanation:

Given

mass of block m=5.7\ kg

at t=0 s

displacement is x=-0.7\ m

velocity v=-0.8\ m/s

acceleration a=2.7\ m/s^2

suppose x=A\cos (\omega t+\phi )   is the general equation of SHM

where A=amplitude

\omega=natural frequency of oscillation

therefore velocity and acceleration is given by

v=-A\omega \sin (\omega t+\phi )

a=A\omega ^2\cos (\omega t+\phi )

for t=0

-0.7=A\cos (\phi )---1

v=-0.8=-A\omega \sin(\phi)---2

a=2.7=-A\omega ^2\cos(\phi )----3

divide 1 and 3 we get

\omega ^2=\frac{27}{7}

\omega =\sqrt{\frac{27}{7}}

Now square and 1 and 2 we get

(0.7)^2+(\frac{0.8}{\omega })^2=A^2

A^2=0.49+0.166

A=0.81\ m

     

3 0
3 years ago
What do you mean by reflection of sound​
Bogdan [553]

Answer:

Reflection of sound waves also leads to echoes. Echoes are different than reverberations. Echoes occur when a reflected sound wave reaches the ear more than 0.1 seconds after the original sound wave was heard. ... Reflection of sound waves off of curved surfaces leads to a more interesting phenomenon.

8 0
3 years ago
!! Offering 50 points !!
Evgesh-ka [11]

Answeryes they are the same

Explanation:

0.5-0.5=10 is gotta be sorry if its wrong

8 0
3 years ago
Read 2 more answers
When attempting to determine the coefficient of kinetic friction, why is it necessary to move the block with constant velocity
Readme [11.4K]

Answer:

Explanation:

In order to measure the coefficient of friction , we apply external force to move the body . When external force comes in motion , we adjust the external force so that it moves with zero acceleration or uniform velocity . In this case external force becomes equal to kinetic frictional force and then net force becomes zero because

net force = mass x acceleration = m x 0 = 0

Now frictional force = μ mg where μ is coefficient of kinetic friction

so F = μ mg where F is external force applied

μ = F / mg

Hence , to make external force equal to frictional force , it is necessary to make acceleration of body zero .

4 0
3 years ago
Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
arsen [322]

Answer:

Given that

speed u=4*10^6 m/s

electric field E=4*10^3 N/c

distance b/w the plates d=2 cm

basing on the concept of the electrostatices

now we find the acceleration b/w the plates  to find the horizontal distance traveled by the electron when it hits the plate.

acceleration a=qE/m=1.6*10^{-19}*4*10^3/9.1*10^{-31} =0.7*10^{15}=7*10^{14} m/s

now we find the horizontal distance traveled by electrons hit the plates

horizontal distance

X=u[2y/a]^{1/2}

=4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}

=3*10^{-2}= 3 cm

5 0
3 years ago
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