Answer:
The answer is 12.67 TMU
Explanation:
Recall that,
worker’s eyes travel distance must be = 20 in.
The perpendicular distance from her eyes to the line of travel is =24 in
What is the MTM-1 normal time in TMUs that should be allowed for the eye travel element = ?
Now,
We solve for the given problem.
Eye travel is = 15.2 * T/D
=15.2 * 20 in/24 in
so,
= 12.67 TMU
Therefore, the MTM -1 of normal time that should be allowed for the eye travel element is = 12.67 TMU
Answer:
<h2>A. a spring & B. a well dried into an aquifer.</h2>
The answer for this question is letter "B.Fission releases energy, and its products have greater stability."
Fission and Fusion are both nuclear reactions that when they release energy, they make the nuclei more stable. So among the choices, option B is the most fitting for the definition.
Depends on what type of mirror that is. I am going to assume this is a plain mirror (from the phrase), which means the height and width of the object and image is exactly the same.
Total distance covered is 47.1 m whereas displacement is zero.
<h3>Calculation:</h3>
Given,
Diameter, d = 5 m
No. of revolutions = 3
Radius, r = 5/2 = 2.5 m
To find,
Distance =?
Displacement =?
Distance covered in one revolution = 2πr
Put the values in this,
Distance = 2 × 3.14 × 2.5
= 15.7 m
Total distance covered in 3 revolution = 3 × 31.4
= 47.1 m
Displacement is the change in the position of the object or the distance between the initial and final position.
After 3 revolutions the particle comes back to its initial position. Therefore, the displacement is zero.
Hence, the total distance covered in 3 resolutions is 47.1 m whereas displacement is zero.
Learn more about distance and displacement here:
brainly.com/question/3243551
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