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n200080 [17]
3 years ago
7

3. What average net force is required to stop a 7 kg shopping cart in 2 s if it's initially

Physics
1 answer:
stiv31 [10]3 years ago
8 0

-12.25N

Explanation:

Given parameters:

Mass of shopping cart = 7kg

Time = 2s

initial velocity = 3.5m/s

Unknown:

Average net force required to stop the cart = ?

Solution;

According to newton's second law"acceleration of body results when a net force acts on a body".

    F = ma

where F is the force

           m is the mass

            a is the acceleration

Acceleration is the change in velocity with time

     a = \frac{v - u}{t}

Therefore;

     F = m x  \frac{v - u}{t}

v is the final velocity, in this case it is zero, 0

u is the initial velocity

t is the time taken

    Putting in the parameters:

      F =  7 x  \frac{0- 3.5}{2} = -12.25N

This force that will stop the cart will be directed in the opposite direction with a magnitude of 12.25N

Learn more:

Newton's law brainly.com/question/11411375

#learnwithBrainly

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Lina20 [59]

Answer:

The final velocity of her partner is approximately -1.04 m/s or 1.04 m/s in the opposite direction to her direction of motion

Explanation:

The given parameters are;

The mass of the man, m₁ = 65 kg

The mass of the woman, m₂ = 45 kg

Taking the relative initial velocity of the man and the woman as 0 m/s, we have;

The initial velocity of the man, v₁₁ = 0 m/s

The initial velocity of the man, v₁₂ = 0 m/s

The final velocity of the woman, v₂₂ = 1.5 m/s

The final velocity of the man = v₂₁

Therefore, we have, by the conservation of momentum principle;

The total initial momentum = The total final momentum

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m₁ × v₁₁ + m₂ × v₁₂ = m₁ × v₂₁ + m₂ × v₂₂

Substituting the known values;

65 × 0 + 45 × 0 = 65 × v₂₁ + 45 × 1.5

∴ 65 × v₂₁ + 45 × 1.5 = 0

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v₂₁ = 45 × 1.5/(-65) ≈ -1.04 m/s

The final velocity of the man, her partner = v₂₁ ≈ -1.04 m/s.

6 0
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A tow truck drags a stalled car along a road. The chain makes an angle of 30???? with the road and the tension in the chain is 1
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Answer: work = 1,305kJ

Explanation:

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force= 1,500N

distance= 1,000m

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R = V/I =  9 / 0.3

R = 30 ohms.
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In a certain time interval, natural gas with energy content of 19000 J was piped into a house during a winter day. In the same t
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Explanation:

Since, it is mentioned the there occurs no change in the temperature. This also means that there will occur no change in thermal energy of the system.

Hence, \Delta E = 0. And, as \Delta E = 0 then there will be no work involved. This means that total energy added to the house will return to the outside air as heat.

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