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3 years ago

Does Ap Physics have anything to do with probablity?

1 answer:

5 0

So I'm a junior. I am currently taking AP Calc BC and AP Physics B.

As of now, I'm not sure if I should take AP Probability and Statistics or Differential Equations/Calc III next year. Also, I'm debating between taking AP Physics C or AP Chemistry.

Which ones do you think would look better on a transcript? I heard that Diffeq/CalcIII is harder than AP ProbStat, but ProbStat is an AP course which will be weighted heavier. Also, should I take Physics C since i've taken Physics B this year already?

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Which of the following defines heredity?

lina2011 [118]

The answer to this question is A.

4 0

3 years ago

a 2kg object is moving horizontally with a speed of 4 m/s.how much net force is required to keep the object moving at this speed

Elza [17]

If the object is moving in a straight line with constant speed,
that's a description of " acceleration = zero ".

Zero acceleration means zero net force on the object.

NO net force is 'required' to keep an object moving in a straight line
at constant speed. In fact, if there IS any net force on the object,
then either its speed or its direction MUST change ... there's no way
to avoid it.

None of this depends on the object's mass, or on the speed or direction
of its motion.

8 0

3 years ago

Two blocks of the same mass but made of different material slide across a horizontal, rough surface and eventually come to rest.

Akimi4 [234]

Answer:

a. $\mathbf{F_{f_2} = 2 F_{f1}}$ , $\mathbf { since \ the \ force \ o f \ friction \ is \ represented \ as \ the \ slope \ for \ each \ of \ the \ two \ curves.}$

Explanation:

From the information given;

Using the work-energy theorem

ΔKE = W = $\mathbf{ F_f \times r}$

K = $\mathbf{ F_f \times r}$

∴

$\dfrac{K_1}{K_2} = \dfrac{F_{f1}}{F_{f2}} (\dfrac{r_1}{r_2})$

Since $K_1 = K_2$ and r_1 = 4, and r_2 = 2 (from the missing diagram which is attached below)

Then;

$1 = \dfrac{F_{f1}}{F_{f2}} (\dfrac{4 \ m}{2 \ m})$

$\mathbf{F_{f_2} = 2 F_{f1}}$

5 0

3 years ago

A 3.0kg mass tied to a string

dem82 [27]

Answer:

$\boxed{\sf Tension \ in \ the \ string \ (T) = 3 \ kN}$

Given:

Mass (m) = 3.0 kg

Uniform speed (v) = 20 m/s

Length of string (r) = 40 cm = 0.4 m

To Find:

Tension in the string (T)

Explanation:

Tension (T) is the string will be equal to centripetal force ( $\sf F_c$ ).

$\boxed{ \bold{ T = F_c = \frac{m {v}^{2} }{r} }}$

Substituting value of m, v & r in the equation:

$\sf \implies T = \frac{3 \times {20}^{2} }{0.4} \\ \\ \sf \implies T = \frac{3 \times 400}{0.4} \\ \\ \sf \implies T =3 \times 1000 \\ \\ \sf \implies T =3000 \: N \\ \\ \sf \implies T =3 \: kN$

$\therefore$

Tension in the string (T) = 3 kN

5 0

3 years ago

What is Motion ?????

Mama L [17]

Answer:

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5 0

3 years ago

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