Answer:
The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.
Explanation:
Explanation:
As it is given that hot pan of copper is dropped into a tub of hot water and the temperature of water rises. This means that heat from the pan has been released and this heat is gained by water.
As a result, temperature of copper pan has decreased and this decrease will continue till the time temperature of both copper pan and water will reach the same temperature.
As thermal energy is defined as the energy in which when two objects come in physical contact with each other then no exchange of heat energy will take place.
Thus, we can conclude that when temperature of both copper pan and water will be equal then it means that both of them has reached thermal equilibrium.
Answer:
0.46km
Explanation:
45963cm/100cm=459.63m/1000m=0.45963 or 0.46km
Answer:
Explanation:
In order to answer this question, we simply have to refer to the laws of the equations of gravitational mechanics.
The equation given by Newton tells us that

In the case where we compare a specific place where the Force of Gravity is greater or lesser, we focus on the term assigned to the Planet's Radius.
In the case of
, we understand that they are constant.
We can easily notice that the more the Radius (Height seen from a viewer on the ground), the lower the force will be.
In other words, the smaller the radius in which the measurement is made with respect to the center of the earth, the greater the gravitational force.
In that order of ideas the smallest radio has South Pole, which is about 6356 km from the center of the Earth on the Equator line
Answer:
The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.
Explanation:
Given that,
Amplitude = 0.08190 m
Frequency = 2.29 Hz
Wavelength = 1.87 m
(a). We need to calculate the shortest transverse distance between a maximum and a minimum of the wave
Using formula of distance

Where, d = distance
A = amplitude
Put the value into the formula


Hence, The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.