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Sphinxa [80]
3 years ago
7

What is thads special talent at the carnival?​

Physics
2 answers:
Bingel [31]3 years ago
4 0

Answer:

wdym

Explanation:

Masja [62]3 years ago
3 0

Answer:

what do uou mean my guy?

Explanation:

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A racetrack has the shape of an inverted cone, as the drawing shows. On this surface the cars race in circles that are parallel
sergey [27]

Answer:

The value of d is 183.51 m.

Explanation:

Given that,

Speed of car = 34.0 m/s

Suppose The car race in the circle parallel to the ground surface is at an angle 40°

The radius of circular path r = d\cos\theta

Normal force acting on the car = N

We need to calculate the value of d

Using component of normal force

The horizontal component of normal force is equal to the gravitational force.

N\cos\theta=mg....(I)

The vertical component of normal force is equal to the centripetal force

N\sin\theta=\dfrac{mv^2}{r}.....(II)

Divided equation (I) by equation (II)

\tan\theta=\dfrac{v^2}{gr}

Put the value of g

\tan\theta=\dfrac{v^2}{g\times d\cos\theta}

v^2=\tan\theta\times g\times d\cos\theta

v^2=g\times d\sin\theta

d=\dfrac{v^2}{g\sin\theta}

Put the value into the formula

d=\dfrac{(34.0)^2}{9.8\times\sin40}

d=183.51\ m

Hence, The value of d is 183.51 m.

3 0
3 years ago
A wrecking ball is suspended by two cables as shown below. If the tension in cable 2 is 12 000 N, what is the weight of the wrec
Paul [167]
Wrecking ball wow get Miley Cyrus also I’m sorry I’m joking bout it and you should report the person who be putting “links”
5 0
2 years ago
A satellite of mass m is in a circular orbit of radius R2 around a spherical planet of radius R1 made of a material with density
Anit [1.1K]

Answer: The gravitational force Fg exerted on the orbit by the planet is Fg = G 4/3πr3rhom/ (R1 + d+ R2)^2

Explanation:

Gravitational Force Fg = GMm/r2----1

Where G is gravitational constant

M Mass of the planet, m mass of the orbit and r is the distance between the masses.

Since the circular orbit move around the planet, it means they do not touch each other.

The distance between two points on the circumference of the two massesb is given by d, while the distance from the radius of each mass to the circumferences are R1 and R2 from the question.

Total distance r= (R1 + d + R2)^2---2

Recall, density rho =

Mass M/Volume V

Hence, mass of planet = rho × V

But volume of a sphere is 4/3πr3

Therefore,

Mass M of planet = rho × 4/3πr3

=4/3πr3rho in kg

From equation 1 and 2

Fg = G 4/3πr3rhom/ (R1 + d+ R2)^2

6 0
3 years ago
A bird is flying due east. Its distance from a tall building is given by x(t) = 28.0 m + (12.4 m/s)t – (0.0450 m/s3)t3. What is
Kruka [31]

Answer:

3.76 m/s

Explanation:

Instantaneous velocity: This can be defined as the velocity of an object in a non uniform motion. The S.I unit is m/s.

v' = dx(t)/dt..................... Equation 1

Where v' = instantaneous velocity, x = distance, t = time.

Given the expression,

x(t) = 28.0 m + (12.4 m/s)t - (0.0450 m/s³)t³

x(t) = 28 + 12.4t - 0.0450t³

Differentiating x(t) with respect to t.

dx(t)/dt = 12.4 - 0.135t²

dx(t)/dt = 12.4 - 0.135t²

When t = 8.00 s.

dx(t)/dt = 12.4 - 0.135(8)²

dx(t)/dt = 12.4 - 8.64

dx(t)/dt = 3.76 m/s.

Therefore,

v' = 3.76 m/s.

Hence, the instantaneous velocity = 3.76 m/s

8 0
2 years ago
How does the force affect the rocks during collisions? *
Jet001 [13]

In a collision, there is a force on both objects that causes an acceleration of both objects; the forces are equal in magnitude and opposite in direction. For collisions between equal-mass objects, each object experiences the same acceleration.
3 0
2 years ago
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