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Sphinxa [80]
3 years ago
7

What is thads special talent at the carnival?​

Physics
2 answers:
Bingel [31]3 years ago
4 0

Answer:

wdym

Explanation:

Masja [62]3 years ago
3 0

Answer:

what do uou mean my guy?

Explanation:

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suppose a ball had a potential energy of 5 j when you dropped it. What would be its kinetic energy just as it hit the ground. (i
Andru [333]
Since we are ignoring air resistance which is a non-conservative force, the potential energy will be completely converted into kinetic energy, resulting in a final kinetic energy of 5J.
4 0
3 years ago
Jamal is skating on a sidewalk. His initial velocity is 0.0 m/s; 35 seconds later his velocity is 5.0 m/s. What is his accelerat
maxonik [38]

Answer:

answer is 0.1428

Explanation:

Data:- vf=5.0 , vi=0.0 , t=35 , a=? so appling first eq of motion vf=vi+at we have to find a=vf-vi/t , a=5.0-0.0/35 , a=5/35 ,a=0.1428m/sec²

5 0
3 years ago
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A mug rests on an inclined surface, as shown in (Figure 1) , θ=17∘.
Anna [14]
Refer to the figure shown below.

g =  9.8 m/s², the acceleration due to gravity.
W = mg, the weight of the mug.
θ = 17°, the angle of the ramp.

Let μ = the coefficient of static friction.

The force acting down the ramp is
F = W sin θ = W sin(17°) = 0.2924W N
The normal reaction is
N = W cosθ = W cos(17°) = 0.9563W N
The resistive force due to friction is
R = μN = 0.9563μW N

For static equilibrium,
μN = F
0.9563μW =0.2924W
μ = 0.3058

The frictional force is F = μN = 0.2924W
The minimum value of μ required to prevent the mug from sliding satisfies
 the condition
R > F
0.9563μW > 0.2924W
μ > 002924/.9563 = 0.306

Answer:
The frictional force is 0.2924mg, where m = the mass of the mug.
The minimum coefficient of static friction is 0.306

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3 years ago
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Squeezing a ball is one
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