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Oksanka [162]
3 years ago
13

When dry ice goes from a solid straight to a gas, it is known as a(n):

Chemistry
1 answer:
RideAnS [48]3 years ago
7 0
Carbon dioxide   СО₂
________________
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What compound name is As5O2
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Answer:

Arsenic pentoxide

Explanation:

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2 years ago
Argon (Ar) and helium (He) are initially in separate compartments of a container at 25°C. The
love history [14]

Answer:

(a) V_B=11.68L

(b) x_{He}=0.533

Explanation:

Hello,

In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:

n_A=\frac{0.082\frac{atm*L}{mol*K}*298K}{1.974 atm*6.00L}=2.063mol

Thus, since the final pressure is 3.60 bar, we can write:

P=x_{Ar}P_A+x_{He}P_B\\\\P=\frac{n_{Ar}}{n_{Ar}+n_{He}} P_A+\frac{n_{He}}{n_{Ar}+n_{He}} P_B\\\\3.60bar=\frac{2.063mol}{2.063mol+n_{He}} *2.00bar+\frac{n_{He}}{2.063mol+n_{He}} *5.00bar

The moles of helium could be computed via solver as:

n_{He}=2.358mol

Or algebraically:

3.60bar=\frac{1}{2.063mol+n_{He}} *(4.0126+5.00*n_{He})\\\\7.314+3.60n_{He}=4.013+5.00*n_{He}\\\\7.314-4.013=5.00*n_{He}-3.60n_{He}\\\\n_{He}=\frac{3.3}{1.4}=2.358mol

In such a way, the volume of the compartment B is:

V_B=\frac{n_{He}RT}{P_B}=\frac{2.358mol*0.082\frac{atm*L}{mol*K}*298.15K}{4.935atm}\\  \\V_B=11.68L

Finally, he mole fraction of He is:

x_{He}=\frac{2.358}{2.358+2.063}\\ \\x_{He}=0.533

Regards.

8 0
2 years ago
1 Smurf = 3 Snorks<br><br> 1 Snork = 6 Pookas<br><br> 8 Pookas = 1 Flintstone1 Smurf = 3 Snorks
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all together you have 13

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you have to add all them together

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3 years ago
If one object has more mass than another then it weighs more or less than the other object?
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It would weigh more: the more mass an object has the more weight is added

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What pressure of carbon dioxide is required to
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The solubility of a gas (Sgas) is directly proportional to its partial pressure (Pgas). what pressure of carbon-dioxide is required to keep the carbon dioxide concentration in a bottle of club soda at 0.12 M at 25 degrees Celsius ? 0.12 M = 3.4 x 10^-2 (Pgas?)
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