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2 years ago

During which of the fallowing chemical changes does a precipitate form??

1 answer:

4 0

<span>A PRECIPITATE is a solid that forms inside of a mixture.
When we add lemon juice to milk, the lemon juice causes lumps to form inside of the milk. SOLID lumps.
We call them "curds." So, we end up with SOLID curds, formed inside of liquid whey.

if that doesn't help its B</span>

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Which would least strongly attract electrons from other atoms in a compound?

sergey [27]

The concept we are looking for here is electronegativity. This concept is a measure of how strong an atom or element can attract a pair, that is bonding, of electrons to itself.

Fluorine is the element or atom of the greatest electronegativity. Electronegativity would increase as we move left to right of the periodic table.

4 0

2 years ago

In the electron cloud model of the atom, an orbital is defined as the most probable(1) charge of an electron

Galina-37 [17]

The correct answer would be 3.) Location of an electron

3 0

2 years ago

A mixture containing 20 mole % butane, 35 mole % pentane and rest

notka56 [123]

Answer:

2.5 % butane, 42.2 % pentane and 55.3 % hexane

Explanation:

Hello,

In this case, the mass balance for each substance is given by:

$Butane:z_bF=y_bD+x_bB\\\\Pentane: z_pF=y_pD+x_pB\\\\Hexane: z_hF=y_hD+x_hB$

Whereas $y$ accounts for the fractions at the outlet distillate and $x$ for the fractions at the outlet bottoms. Moreover, with the 90 % recovery of butane, we can write:

$0.9=\frac{y_bD}{z_bF}$

So we can compute the product of the molar fraction of butane at the distillate by total distillate flow by assuming a 100-mol feed:

$y_bD=0.9*z_bF=0.9*0.2*100mol=18mol$

The total distillate flow:

$y_bD=18mol\\\\D=\frac{18mol}{0.95} =18.95mol$

And the total bottoms flow:

$F=D+B\\\\B=F-D=100mol-18.95mol=81.05mol$

Next, by using the mass balance of butane, we compute the molar fraction of butane at the bottoms:

$x_b=\frac{z_bF-y_bD}{B} =\frac{0.2*100mol-18mol}{81.05} =0.025$

Then, the molar fraction of pentane and hexane:

$x_p=\frac{z_pF-y_pD}{B} =\frac{0.35*100mol-0.04*18.95mol}{81.05} =0.422$

$x_h=\frac{z_hF-y_hD}{B} =\frac{(1-0.2-0.35)*100mol-(1-0.95-0.04)*18.95mol}{81.05} =0.553$

Therefore, the molar composition of the bottom product is 2.5 % butane, 42.2 % pentane and 55.3 % hexane.

NOTE: notice the result is independent of the value of the assumed feed, it means that no matter the basis, the compositions will be the same for the same recovery of butane at the feed, only the flows will change.

Regards.

8 0

2 years ago

Read 2 more answers

Question 8

nexus9112 [7]

72 degrees C (minus 273)

6 0

2 years ago

Which list includes three types of chemical reactions?

Sidana [21]

Answer=3

<span>Decomposition, double replacement, and synthesis are 3 types of chemical reactions.</span>