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slavikrds [6]
4 years ago
13

When the temperature of an ideal gas is increased, what happens to its pressure?

Physics
1 answer:
lorasvet [3.4K]4 years ago
6 0
<h2>Answer: Its pressure is also increased</h2>

Explanation:

The expression for an Ideal Gas is:

P.V=n.R.T

Where:

P is the pressure of the gas

n the number of moles of gas

R is the gas constant

T is the absolute temperature of the gas

As we can see, <u>there is a direct proportional relation between the temperature and the pressure</u>, which means that if the temperature increases the pressure of the gas increases as well.

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A racecar accelerates uniformly from 18.5 mil to 46.1 m/s in 2.47 seconds.
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Answer:

<em>The acceleration of the racecar is</em> \mathbf{11.17~m/s^2}

Explanation:

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Following the definition above, the acceleration is defined as:

\displaystyle a=\frac{v_f-v_o}{t}

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3 years ago
Choose the +x-direction to point to the right. • Object 1 has a mass 1.66 kg and is moving to the right at 11.2 m/s. • Object 2
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Answer:

M = 49.4kgm/s (towards the left)

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Momentum is the product of mass and velocity of an object

Momentum = mass * velocity

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M1 = 1.66 * 11.2

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M2 = 6.59 * -10.4

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M = M1+M2

M = 18.592kgm/s--68.536kgm/s

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M = 49.4kgm/s (towards the left)

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