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chubhunter [2.5K]
3 years ago
9

Help!! If an atom has 7 protons and 8 neutrons, and is not in an excited state, how many electrons would Bohr say the atom has?

Physics
2 answers:
quester [9]3 years ago
8 0
The answer I believe is 6
belka [17]3 years ago
8 0

Answer:

its either 15 or 8

Explanation:

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2. Two projectiles thrown from the same point at angles 0,=60° and 02=30° with the horizontal,
Liono4ka [1.6K]

Answer:

The answer is below

Explanation:

The maximum height (h) of a projectile with an initial velocity of u, acceleration due to gravity g and at an angle θ with the horizontal is given as:

h=\frac{u^2sin^2\theta}{2g}

Given that the two projectile has the same height.

For\ the\ first\ projectile\ with\ an\ angle\ \60^0 \ with\ the\ horizontal\ and initial\ velocity\ u_1:\\\\h=\frac{u_1^2sin^260}{2g} =\frac{0.75u_1^2}{2g} \\\\For\ the\ second\ projectile\ with\ an\ angle\ \30 \ with\ the\ horizontal\ and initial\ velocity\ u_2:\\\\h=\frac{u_2^2sin^230}{2g} =\frac{0.25u_2^2}{2g}\\\\\frac{0.25u_2^2}{2g}=\frac{0.75u_1^2}{2g}\\\\0.25u_2^2=0.75u_1^2\\\\\frac{u_1^2}{u_2^2} =\frac{0.25}{0.75} \\\\\frac{u_1^2}{u_2^2}=\frac{1}{3} \\\\\frac{u_1}{u_2}=\sqrt\frac{1}{3}

8 0
3 years ago
Light traveling from water to a gemstone strikes the surface at an angle of 80.0º and has an angle of refraction of 15.2º . (a)
7nadin3 [17]

Answer:

a

The the speed of light in the gemstone is  v= 0.599*10^8 m/s

b

The unreasonable thing about this is that the speed of ligth in the gemstone is too low

the speed is 19% of the speed of light  which is very low

c

One main unreasonable or inconsistent factor is that the assumption that the  differnce between the angle of incidence and angle of refraction is  very large

Explanation:

  From the question we are told that

       The  angle of incidence  i = 80^o

        The angle of refraction  r = 15.2^o

From Snell's law we have ,

      n_1 sin \theta_1 = n_2 sin \theta_2

    Where n_1 is the refractive index of the first medium (water) with a constant value  of  n_1 = 1..333

                n_2  is the refractive index of the second medium (gem stone)

                 \theta_1 is the angle between  the beam and perpendicular surface of the first medium

               \theta_2  is the angle  between the beam an the perpendicular surface of the second medium

      Making  the n_2 the subject of the formula

                       n_2 = n_1 \frac{sin \theta_1}{sin \theta_2}

                           = (1.333)(\frac{sin (80.0)}{sin  15.2} )

                           = 5.007

 Generally refractive index of a material  is mathematically represented

                      n = \frac{c}{v}

 Where c is the speed light

               v is the speed of light  observed in a medium

 Making v the subject

            v = \frac{c}{n}

 substituting value for gem stone

          v  =  \frac{3.0*10^8}{5.007}

              v= 0.599*10^8 m/s

     

               

7 0
3 years ago
Define resistance and describe what would happen to a light bulb if the voltage increased but the resistance stayed the same. Re
Anarel [89]

Answer:

The light bulb would glow brighter.

Explanation:

Resistance is the opposition to current flow and in Ohm's law is represented as a constant in the equation V = IR with V the voltage, I the current and R the resistance.

Now let's assume we are in a series circuit that has only one path for electricity to follow to better explain what would happen to a light bulb if the voltage increased but the resistance stayed the same. Based on ohm's law equation, the voltage is directly proportional to the current and the resistance is constant. An increase in the voltage is therefore an increase in the current  which flows throught the light bulb making it glow brighter while a decrease in voltage results in a decrease in current flowing through the light bulb making it dim.

8 0
3 years ago
Given the thermochemical equations X2+3Y2⟶2XY3ΔH1=−370 kJ X2+2Z2⟶2XZ2ΔH2=−120 kJ 2Y2+Z2⟶2Y2ZΔH3=−270 kJ Calculate the change in
Alchen [17]

Answer : The change in enthalpy of the reaction is, -310 kJ

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main reaction is,

4XY_3+7Z_2\rightarrow 6Y_2Z+4XZ_2    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) X_2+3Y_2\rightarrow 2XY_3     \Delta H_1=-370kJ

(2) X_2+2Z_2\rightarrow 2XZ_2    \Delta H_2=-120kJ

(3) 2Y_2+Z_2\rightarrow 2Y_2Z    \Delta H_3=-270kJ

Now we will reverse the reaction 1 and multiply reaction 1 by 2, reaction 2 by 2 and reaction 3 by 3 then adding all the equations, we get :

(1) 4XY_3\rightarrow 2X_2+6Y_2     \Delta H_1=2\times (+370kJ)=740kJ

(2) 2X_2+4Z_2\rightarrow 4XZ_2    \Delta H_2=2\times (-120kJ)=-240kJ

(3) 6Y_2+3Z_2\rightarrow 6Y_2Z    \Delta H_3=3\times (-270kJ)=-810kJ

The expression for enthalpy of formation of CH_4 will be,

\Delta H=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+740kJ)+(-240kJ)+(-810kJ)

\Delta H=-310kJ

Therefore, the change in enthalpy of the reaction is, -310 kJ

5 0
3 years ago
A long line of charge with uniform linear charge density λ1 is located on the x-axis and another long line of charge with unifor
Dahasolnce [82]

Answer:

A.The positive z-direction

Explanation:

We are given that

Linear charge density of long line which is  located on the x-axis=\lambda_1

Linear charge density of another long line which is  located on the y-axis=\lambda_2

We have to find the direction of electric field at z=a on the positive z-axis if \lambda_1 and \lambda_2 are positive.

The direction of electric field  at z=a on the positive z-axis  is positive z-direction .

Because \lambda_1 and \lambda_2 are positive and the electric field is  applied away from the positive charge.

Hence, option A is true.

A.The positive z-direction

6 0
3 years ago
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