Answer:
The two most common types of orbit are "geostationary" and "polar."
Answer:
P = 1 (14,045 ± 0.03 ) k gm/s
Explanation:
In this exercise we are asked about the uncertainty of the momentum of the two carriages
Δ (Pₓ / Py) =?
Let's start by finding the momentum of each vehicle
car X
Pₓ = m vₓ
Pₓ = 2.34 2.5
Pₓ = 5.85 kg m
car Y
Py = 2,561 3.2
Py = 8,195 kgm
How do we calculate the absolute uncertainty at the two moments?
ΔPₓ = m Δv + v Δm
ΔPₓ = 2.34 0.01 + 2.561 0.01
ΔPₓ = 0.05 kg m
Δ
= m Δv + v Δm
ΔP_{y} = 2,561 0.01+ 3.2 0.001
ΔP_{y} = 0.03 kg m
now we have the uncertainty of each moment
P = Pₓ /
ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²
ΔP = 8,195 0.05 + 5.85 0.03 / 8,195²
ΔP = 0.006 + 0.0026
ΔP = 0.009 kg m
The result is
P = 14,045 ± 0.039 = (14,045 ± 0.03 ) k gm/s
complex carbohydrates, such as starches and fiber, provide the body with long-lasting energy.
Hope this helps!
Answer:
The first part of the question is asking about BUOYANT FORCE or UPTHRUST.
Upthrust =TRUE WEIGHT-APPARENT WEIGHT
TRUE WEIGHT=mg
TRUE weight=50kg×10m/s²
=500N
upthrust=500N-380N
FB=120N
volume of the rock=mass/density.
since the granite is completely submerged, the volume of the displaced liquid will be equal to the volume of the body.
upthrust=Vdg
120N=V×1000kg/m³×10m/s²
120N=V×10000kg/m²s²
120/10000=V
v=0.012m³
please mark brainliest, hope it helped
Answer:
V = (Vx^2 + Vy^2)^1/2 = (40^2 + 62^2)^1/2
V = 73.8 m/s
tan theta = Vy / Vx = 62/40 = 1.55
theta = 57.2 deg