I think it is force of acceleration but I'm not sure.. hope this helps though!
Answer:
Amine have higher boiling points than hydrocarbons.
Explanation:
Primary, secondary and tertiary amines have higher boiling points than hydrocarbons because they can engage in intermolecular hydrogen bonding.
Amines has three classes
1. Primary amines
2. Secondary amines
3. Tertiary amines
All this classes of amines have higher boiling point than hydrocarbons due to C-N bond in them
This is because amines can engage in hydrogen bonding with water, amines of low molar mass are quite soluble in water.
Amines are having higher boiling points than hydrocarbons, as C-N bond in amines is more polar than a C-C bond in hydrocarbons. Due to the polar nature of amines, it forms intermolecular H-bonds and exists as associated molecules.
Answer:
Option B
Explanation:
The electrons flow from negative terminal of a battery to the positive terminal because as the charge of electron is negative, it will get repelled by the negative terminal of the battery
Conventional flow actually assumes that the current flows out of the positive terminal, through the circuit and into the negative terminal of the battery
It actually says that direction of flow of current is in opposite direction to the direction of flow of electrons
The direction of current will not change even a resistor is placed in the circuit and it generates a potential difference across the resistor
But the current tries to move in such a way in which there will be less resistance to the flow
Answer:
Explanation:
a )
initial velocity u = 45 m/s
acceleration a = - 5 m/s²
final velocity v = 0
v = u - at
0 = 45 - 5 t
t = 9 s
b )
s = ut - 1/2 at²
= 45 x 9 - .5 x5x 9²
405 - 202.5
202.5 m
2 )
a )
s = ut + 1/2 a t²
u = 0
s = 1/2 at²
= .5 x 9.54 x 6.5²
= 201.5 m
b )
v = u + at
= 0 + 9.54 x 6.5
= 62.01 m / s
3
a )
acceleration = (v - u) / t
= (34 - 42) / 2.4
= - 3.33 m /s²
b )
v² = u² - 2 a s
34² = 42² - 2 x 3.33² s
s = 27.41 m
c )
Average velocity
Total displacement / time
= 27.41 / 2.4
= 11.42 m /s
4 )
a )
v = u + at
v = 0 + 3 x 4
= 12 m /s
b )
s = ut + 1/2 a t²
= o + .5 x 3 x 4²
= 24 m
The intensity of the electric field is 30,000 N/C
Explanation:
The strength of the electric field produced by a single-point charge is given by the equation
where:
is the Coulomb's constant
q is the magnitude of the charge
r is the distance from the charge
In this problem, we have:
is the magnitude of the charge
r = 3 cm = 0.03 m is the distance at which we are calculating the field intensity
Substituting, we find:
Learn more about electric field:
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