Answer:
0.9483 grams of manganese dioxide should be added to excess HCl.
Explanation:
Pressure of the chlorine gas = P = 795 Torr = 1.046 atm (1 atm = 760 Torr)
Volume of the chlorine gas = V = 255 ml = 0.255 L
Temperature of the chlorine gas = T = 25°C= 298.15 K
Moles of chlorine gas = n
Using ideal gas equation:
PV = nRT

n = 0.01090 mol

According to reaction , 1 mole of chlorine gas is obtained from 1 mole of manganese dioxide.
Then 0.01090 moles of chlorine gas will be obtained from:
manganese dioxide
Mass of 0.01090 moles of manganese dioxide:
0.01090 mol × 87 g/mol = 0.9483 g
Reaction type : Double-Replacement reactions
<h3>Further explanation</h3>
Given
Reaction
MgCl2 +
Li2CO3 →
MgCO3 +
LiCl
Required
Balanced equation
Reaction type
Solution
Balanced equation
Li2CO3 (s) + MgCl2 (aq) → MgCO3 (s) + 2 LiCl (aq)
Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product
To predict whether this reaction can occur or not is one of them, the precipitation reaction.
MgCO3 is a precipitation compound
Answer:
the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals
Explanation:
Answer:
There is an extra O2 molecule left over
Explanation:
Answer:
3.4 × 10
^−
4
Explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the
10
. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.