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pickupchik [31]
3 years ago
9

Typical frequencies for several types of electromagnetic radiation are given below. Calculate the energy of each type of radiati

on.
a. A gamma ray: ν = 1.64 ✕ 10^20 s^−1
b. A microwave: ν = 4.95 ✕ 10^10 s^−1
c. An AM radio wave: ν = 2.00 ✕ 10^6 s^−1
Chemistry
1 answer:
marusya05 [52]3 years ago
4 0

Explanation:

The energy of electromagnetic radiation is given by :

E=h\nu

Where, h is the Planck's constant

(a) A gamma ray, \nu = 1.64\times 10^{20}\ Hz

Energy,

E=6.63\times 10^{-34}\times 1.64\times 10^{20}\\E=1.08\times 10^{-13}\ J

(b) A microwave, \nu = 4.95\times 10^{10}\ Hz

Energy,

E=6.63\times 10^{-34}\times 4.95\times 10^{10}\\E=3.28\times 10^{-23}\ J

(c) A AM radio wave, \nu = 2\times 10^{6}\ Hz

Energy,

E=6.63\times 10^{-34}\times 2\times 10^{6}\\E=1.32\times 10^{-27}\ J

Therefore, this is the required solution.

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How many mL of a 1.48 M calcium hydroxide solution are needed to neutralize 36.0 mL of a 1.63 M hydrochloric acid solution
Lelechka [254]

The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL

<h3>Balanced equation </h3>

2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O

From the balanced equation above,

  • The mole ratio of the acid, HCl (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 1

<h3>How to determine the volume of Ca(OH)₂ </h3>
  • Molarity of base, Ca(OH)₂ (Mb) = 1.48 M
  • Volume of acid, HCl (Va) = 36 mL
  • Molarity of acid, HCl (Ma) = 1.63 M
  • Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(1.63 × 36) / (1.48 × Vb) = 2

58.68 / (1.48 × Vb) = 2

Cross multiply

2 × 1.48 × Vb = 58.68

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Divide both side by 2.96

Vb = 58.68 / 2.96

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The combustion reaction of octane is as follow,

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According to balance equation,

8 moles of CO₂ are released when  =  114.23 g (1 mole) Octane is reacted

So,

      6.20 moles of CO₂ will release when  =  X g of Octane is reacted

Solving for X,
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                                     X  =  88.52 g of Octane
Result:
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