All categories

3 years ago

Which resources are significantly polluted by heavy metals like mercury?

Chemistry

2 answers:

Scrat [10]3 years ago

6 0

Answer D!!! both A and B

Explanation:

arlik [135]3 years ago

4 0

<span>Heavy metals like mercury enter waterways by industrial dumping and poor regulatioin of effluent, and they also enter soil through a similar manner, in which waste is disposed of imporperly. Another source of heavy metals are the gases leaving industry carrying these metals. The metals fall as a solid on to soil and water ways. Therefore, the answer is D.</span>

You might be interested in

PLEASE HELP!!

Andrews [41]

The answer should be B. hope this helped ;)

3 0

2 years ago

who else has found that something they did or readed or whatever it is they had completely forgot about and just remembered abou

Dominik [7]

Answer:

Yes I do this a lot :)

Explanation:

6 0

2 years ago

Nitrogen gas (N2) and hydrogen gas (H2) react to produce ammonia (NH3).

WINSTONCH [101]

Answer:

I believe it would be 2

Explanation:

if there are 2 nitrogen molecules then there would have to be 2 hydrogen molecules but this could be completely wrong

if this happens to be right, ur welcome :3 here's a Jay Jay pic for u cuz why not

8 0

2 years ago

If a lab requires each a lab group (3 students) to have 25 ml of a solution and it takes 15 grams of AgNO₃ cuprous nitrate, to m

pochemuha

Answer:

0.375 grams are needed to make 25 mL solution.

Explanation:

Mass of $AgNO_3$ cuprous nitrate required to make 1 l of solution = 15 g.

1 L = 1000 mL

Mass of $AgNO_3$ cuprous nitrate required to make 1000 mL of solution = 15 g

Mass of $AgNO_3$ cuprous nitrate required to make 1 mL of solution:

$=\frac{15}{1000} g$

Mass of $AgNO_3$ cuprous nitrate required to make 25 mL of solution:

$=\frac{15}{1000} \times 25 g=0.375 g$

0.375 grams are needed to make 25 mL solution.

4 0

3 years ago

There are 85.63 g of CO2 gas in a container maintained at STP. How many liters of CO2 are there in that container?

konstantin123 [22]

Answer:

V = 48.64 L

Explanation:

Given data:

Mass of CO₂ = 85.63 g

Temperature = 273 K

Pressure = 1 atm

Volume of CO₂ = ?

Solution:

Number of moles of CO₂:

Number of moles = mass/molar mass

Number of moles = 85.63 g / 40 g/mol

Number of moles = 2.14 mol

Volume in Litter:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

1 atm× V = 2.14 mol ×0.0821 atm.L/mol.K ×273 K

V = 48.64 atm.L / 1 atm

V = 48.64 L

7 0

2 years ago