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3 years ago

A chemical bond between two atoms results from a simultaneous

Chemistry

2 answers:

Elena L [17]3 years ago

7 0

If you are asking for the word for this definition it is a <span>attraction by the two nucluei</span>

Sedbober [7]3 years ago

5 0

Answer:

B. attraction by the two nuclei for the electrons

Explanation:

From Castle Learning

The positive protons located in the nucleus attract a pair of electrons which forms a bond between atoms

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When you have dominant allele T, recessive for t, T for tall and t for short, what will be phenotype for Tt?

Dmitry_Shevchenko [17]

Answer:

TT and Tt genotypes both expressed the tall phenotype because the T is dominant to t. Only the tt genotype expressed the short phenotype.

Explanation:

Hope this helped!

8 0

3 years ago

A light source of wavelength, l, illuminates a metal and ejects photoelectrons with a maximum kinetic energy of 1 eV. A second l

madreJ [45]

Explanation:

From first source, kinetic energy ( $K.E_{1}$ ) ejected is 1 eV and wavelength of light is $\lambda$ .

From second source, kinetic energy ( $K.E_{2}$ ) ejected is 4 eV and wavelength of light is $\frac{\lambda}{2}$ .

Relation between work function, wavelength, and kinetic energy is as follows.

K.E = $\frac{hc}{\lambda} - \phi$

where, h = Plank's constant = $6.63 \times 10^{-34}$ J.s

c = speed of light = $3 \times 10^{8}$ m/s

Also, it is known that 1 eV = $1.6 \times 10^{-19}$ J

Therefore, substituting the values in the above formula as follows.

From first source,

$K.E_{1}$ = $\frac{hc}{\lambda} - \phi$

1 eV = $1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\lambda} - \phi$

$1.6 \times 10^{-19} J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (1)

From second source,

$K.E_{2}$ = $\frac{hc}{\lambda} - \phi$

$4 \times 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\frac{\lambda}{2}} - \phi$

$6.4 \times 10^{-19} J = \frac{2 \times 1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (2)

Now, divide equation (2) by 2. Therefore, it will become

${6.4 \times 10^{-19}J}{2} = \frac{2 \times 1.98 \times 10^{-25} J.m}{2\lambda} - \frac{\phi}{2}$

$3.2 \times 10^{-19}J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \frac{\phi}{2}$ ......... (3)

Now, subtract equation (3) from equation (1), we get the following.

$1.6 \times 10^{-19} = \frac{\phi}{2}$

$\phi$ = $3.2 \times 10^{-19}$

= 2 eV

Thus, we can conclude that work function of the metal is 2 eV.

3 0

4 years ago

Is radium usually considered as part of the alkaline earth category in terms of chemistry?

victus00 [196]

Explanation:

Radium (atomic number 88) has similar properties to barium and is also in the Group 2 category. However, radium is a radioactive element and is generally under the category of radioisotopes in addition to being an alkaline earth metal, because it is not a stable element.

4 0

3 years ago

Magnesium and nitrogen react to form magnesium nitrate. Which of the following expressions represents this chemical reaction?

Leona [35]

Magnesium + Nitrogen ➡ Magnesium Nitrate

3 0

3 years ago

Plz answer question number 1,2,4,5 and 6

yulyashka [42]

Answer:

1.Handpicking,winnowing and sieving 2. distillation 3.distillation 5. winnowing 6.magnet

4 0

3 years ago