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marishachu [46]
3 years ago
9

What is the absolute value of negative one and one third?

Mathematics
2 answers:
ella [17]3 years ago
3 0
The absolute value of negative one and one third is one and one third because to find the absolute value you just count the spaces from zero and an absolute value can never be negative so the absolute value is 1 and 1/3.
Airida [17]3 years ago
3 0

Answer:

Absolute Value function.

Step-by-step explanation:

  • Absolute Value refers to the distance of a number from 0, the distances are positive regardless of the direction of distance.
  • Absolute value of a number cannot be negative as distance is always positive.
  • Absolute value function can be defined as

f(x) = \mid x \mid = x, x > 0\\~~~~~~~~~~~~~~= -x, x < 0

1)

f(-1) = \mid -1 \mid = -(-1) = 1

2)

f(\frac{1}{3}) = \mid \frac{1}{3} \mid = \frac{1}{3}

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Please help me fast I still nee to finish 2 more ixl's by monday!!!!
sleet_krkn [62]

Answer:No

Step-by-step explanation:

Given system of equation is:

2x + 3 = y

2x + y = 15

To check whether (2,7) is solution to this system or not, we will put x=2 and y=7 in both equations.

Putting x=2 and y=7 in Eqn 1

2(2) + 3 = 7

4 + 3 = 7

7 = 7

Thus the ordered pair satisfies the equation

Putting x=2 and y=7 in Eqn 2

2(2) + 7 = 15

4 + 7 = 15

11 ≠ 15

The ordered pair do not satisfy the second equation.

Hence,

(2,7) is not a solution to the given system of equations.

3 0
3 years ago
Evaluate the six trigonometric functions of the angle 0.
Arturiano [62]

Given:

Right triangle

To find:

The six trigonometric functions of θ

Solution:

Hypotenuse = 18

Adjacent side to θ = 10

Opposite side to θ = ?

Using Pythagoras theorem:

\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2

18^2 =10^2+\text{opposite}^2

324=100+\text{opposite}^2

Subtract 100 from both sides.

224=\text{opposite}^2

Taking square root on both sides.

4\sqrt{14}=\text{opposite}

Using trigonometric ratio formula:

$\sin\theta =\frac{\text{opposite }}{\text{hypotenuse}}

$\sin\theta =\frac{4\sqrt{14} }{18}

$\csc\theta =\frac{\text{hypotenuse}}{\text{opposite }}

$\csc\theta =\frac{18}{4\sqrt{14} }

$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}

$\cos \theta=\frac{10}{18}

$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}

$\sec \theta=\frac{18 }{10}

$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}

$\tan \theta=\frac{4\sqrt{14} }{10}

$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}

$\cot \theta=\frac{10}{4\sqrt{14} }

8 0
3 years ago
40.51x+12.45y=666.64
irga5000 [103]

Answer:

The graph of the equation 40.51x+12.45y=666.64 is attached with the answer where the horizontal axis represents the X axis and the vertical axis represents Y axis.

To plot the graph physically just find two points lying on the line. Mark the points on the graph sheet and then join them. This will give you the line represented by the equation.

To find points on the line assume the value of any one variable, substitute it in the equation, then solve the equation to find the value of other variable. For example : assume y = 1; substitute the value of y in the equation;

⇒ 40.51x + 12.45×1 = 666.64

⇒ 40.51x = 666.64 - 12.45

⇒ 40.51x = 654.19

⇒ x = \frac{654.19}{40.51}

⇒ x ≈ 16.149

Therefore point ( 16.149 , 1 ) lie on the graph of the equation.

***Only two points are required to plot this graph just because it represents a straight line, that we can conclude just by observing the equation. If in an equation the power of x is 1 or 0 and power of y is 1 or 0 then only it will represent a straight line in 2-D plane.***

5 0
3 years ago
(02.04 MC)
borishaifa [10]

Answer:

umm idk let me get back to you

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve the system by the addition method <br> 4x=3y-8<br> -16x+4y=32
butalik [34]
4x = 3y - 8
 4         4
  x = ³/₄y - 2

                  -16x + 4y = 32
       -16(³/₄y - 2) + 4y = 32
-16(³/₄y) + 16(2) + 4y = 32
          -12y + 32 + 4y = 32
          -12y + 4y + 32 = 32
                    -8y + 32 = 32
                           - 32  - 32
                            -8y = 0
                             -8    -8
                               y = 0
x = ³/₄y - 2
x = ³/₄(0) - 2
x = 0 - 2
x = -2

(x, y) = (-2, 0)
6 0
3 years ago
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