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3 years ago

State whether the equation is true, false, or an open sentence. 3(5 – 5) = –6(–2 + 2)

Mathematics

1 answer:

jonny [76]3 years ago

8 0

True.

Remember to follow PEMDAS. First, solve the parenthesis, then multiply

5 - 5 = 0

3(0) = 0

-2 + 2 = 0

-6(0) = 0

0 = 0 ∴ true is your answer

hope this helps

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The length of a rectangle is 3 less than twice the width. Write a function rule for the perimeter in terms of w, the width

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l = 2w-3

P = 2(l+w)

substitute in for l

P = 2(2w-3 +w)

combine like terms

P = 2(3w-3)

P = 6w-6

P(w) = 6(w-1)

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3 years ago

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A LINE SEGMENT IS 5 INCHES MORE THAN FOUR TIMES THE LENGTH OF ANOTHER. THE DIFFERENCE IN THEIR LENGTHS IS 35 INCHES. HOW LONG AR

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<h3>Answer:</h3>

One line segment is 10 cm and the other one is 45 cm

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3 years ago

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Stolb23 [73]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

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Multiply the cost per hour by 32 hrs to get the total amount he'll get paid:

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3 years ago

A racecar travels 225 miles per hour. How far will it drive in 6 1/2 hours?

saul85 [17]

Answer:

1462.5

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225 mph means of course 225 miles per hour

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3 years ago

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A line passes through point A(10,15). A second point on the line has an x-value that is 125% of the x-value of point A and a y-v

melisa1 [442]

The equation of the line in the point-slope form is y - 15 = $-\frac{3}{2}$ (x - 10)

Step-by-step explanation:

The point-slope form of a linear equation is $y-y_{1}=m(x-x_{1})$ , where

m is the slope of the line, where $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ , $(x_{1},y_{1})$ and $(x_{2},y_{2})$ are two points on the line
$(x_{1},y_{1})$ is a point on the line

∵ Point A = (10 , 15)

∵ The x-coordinate of the second point is 125% of x-coordinate

of point A

∴ x-coordinate of second point = $\frac{125}{100}$ × 10

∴ x-coordinate of second point = 12.5

∵ The y-coordinate of the second point is 75% of y-coordinate

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∴ y-coordinate of second point = $\frac{75}{100}$ × 15

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∴ The coordinates of the second point are (12.5 , 11.25)

Let us find the slope of the line by using the rule of it above

∵ $(x_{1},y_{1})$ = (10 , 15)

∵ $(x_{2},y_{2})$ = (12.5 , 11.25)

∴ $m=\frac{11.25-15}{12.5-10}=\frac{-3.75}{2.5}=-\frac{3}{2}$

Now we can write the equation

∵ The point-slope form is $y-y_{1}=m(x-x_{1})$

∵ $m=-\frac{3}{2}$

∵ $(x_{1},y_{1})$ = (10 , 15)

- Substitute these values in the form of the equation

∴ y - 15 = $-\frac{3}{2}$ (x - 10)

The equation of the line in the point-slope form is y - 15 = $-\frac{3}{2}$ (x - 10)

Learn more:

You can learn more about the linear equation in brainly.com/question/4152194

#LearnwithBrainly

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