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4 years ago

The amount of potential energy possessed by an elevated object is equal to

Physics

1 answer:

Sedbober [7]4 years ago

4 0

Answer:

Potential energy of the object will be equal to mgh

Explanation:

Let the mass of the object is m

Acceleration due to gravity is $gm/sec^2$

Let the object is released from height h

We have to find the potential energy

Potential energy is of an object released from height h is equal to

$U=mgh$ , here m is mass, g is acceleration due to gravity and h is height from which object is released.

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Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez

Zanzabum

(a) $3.3\cdot 10^{-6} Pa$

The radiation pressure exerted by an electromagnetic wave on a surface that totally absorbs the radiation is given by

$p=\frac{I}{c}$

where

I is the intensity of the wave

c is the speed of light

In this problem,

$I=1000 W/m^2$

and substituting $c=3\cdot 10^8 m/s$ , we find the radiation pressure

$p=\frac{1000 W/m^2}{3\cdot 10^8 m/s}=3.3\cdot 10^{-6}Pa$

(b) $4.4\cdot 10^{-8} m/s^2$

Since we know the cross-sectional area of the laser beam:

$A=6.65\cdot 10^{-29}m^2$

starting from the radiation pressure found at point (a), we can calculate the force exerted on a tritium atom:

$F=pa=(3.3\cdot 10^{-6}Pa)(6.65\cdot 10^{-29} m^2)=2.2\cdot 10^{-34}N$

And then, since we know the mass of the atom

$m=5.01\cdot 10^{-27}kg$

we can find the acceleration, by using Newton's second law:

$a=\frac{F}{m}=\frac{2.2\cdot 10^{-34} N}{5.01\cdot 10^{-27} kg}=4.4\cdot 10^{-8} m/s^2$

6 0

4 years ago

What services do plants provide? Select the three that apply.

Irina18 [472]

The answer to this is B, C, and D. hope this helped

6 0

3 years ago

1. *A car is going over the top of a hill whose curvature approximates a circle of radius 200 m. At

Greeley [361]

Answer:

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s

Explanation:

The given parameters are;

The curvature of the hill, r = 200 m

Due to the velocity, v, the occupants weight = 20% less than the normal weight

The outward force of an object due to centripetal (motion) force is given by the following equation;

$F_c = \dfrac{m \times v^2}{r}$

Where;

r = The radius of curvature of the hill = 200 m

Given that the weight of the occupants, W = m × g, we have;

$F_c = 0.2 \times W = 0.2 \times m \times g$

$\therefore 0.2 \times m \times g = \dfrac{m \times v^2}{r}$

v = √(0.2 × g × r)

By substitution, we have;

v = √(0.2 × 9.81 × 200) ≈ 19.81

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.

3 0

3 years ago

When you have been swimming swimming and you come out of the pool, you may feel cold. Use your understanding of endothermic proc

Leona [35]

Explanation:

Edothermic process is the absorbtion of heat.

It is the opposite of exothermic process which is the release of energy. In edothermic process thermal energy is absorbed from the surrounding

4 0

3 years ago

A viscous fluid is flowing through two horizontal pipes. The pressure difference P1 - P2 between the ends of each pipe is the sa

777dan777 [17]

Answer:half of shorter Pipe

Explanation:

Fluid is Flowing through two horizontal pipes with pressure difference

$P_1-P_2=\Delta P$

Both pipes have same radius

Length of one Pipe is twice of other

Let Longer Pipe be denote by 1 and smaller by 2

From Hagen Poiseuille equation

$\Delta P=\frac{128\mu L\cdot Q}{\pi D^4}$

Where $\mu =$ viscosity of medium

L=length of Pipe

Q=discharge

D=diameter

For longer Pipe

$\Delta P=\frac{128\mu 2L\cdot Q_1}{\pi \cdot D^4}$ ----1

For smaller Pipe

$\Delta P=\frac{128\mu L\cdot Q_2}{\pi \cdot D^4}$ ------2

From 1 & 2 we get

$2L\cdot Q_1=L\cdot Q_2$

$Q_2=2Q_1$

volume flow rate of longer pipe is half of smaller pipe

6 0

3 years ago