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Zanzabum
3 years ago
11

What is the amount of "stuff in an object?

Physics
2 answers:
ziro4ka [17]3 years ago
7 0

mass is  the amount of "stuff in an object

Andrei [34K]3 years ago
4 0
Good question. The amount of 'stuff' in an object is it's mass. 

A fundamental distinction we learn in physics is the difference between mass and weight. If we were in deep space, away from any very large objects of mass (like a planet), we would be 'weightless' e.g. not feel the effects of gravity, but we would not be 'massless'. Our mass doesn't change based upon our proximity to large objects (gravitational attraction), but the sense of weight does.
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This equation is known as the ideal gas law, and it can be used to predict the behavior of many gases at relatively low pressure
Masja [62]
The correct answer is 
<span>C) either the pressure of the gas, the volume of the gas, or both, will increase.

In fact, the ideal gas law can be written as
</span>pV=nRT
<span>where 
p is the gas pressure
V is its volume
n is the number of moles
R is the gas constant
T is the absolute temperature of the gas

We can see that if the temperature T increases, then the term on the right in the equation increases, therefore the term on the left should increase as well. In order for this to be possible, at least one between p and V should increase, or also both of them. Therefore, the correct answer is C.</span>
6 0
3 years ago
An airplane flies in a loop (a circular path in a vertical plane) of radius 160 m . The pilot's head always points toward the ce
notka56 [123]

Answer:

a) 39.6 m/s b) 4123 N

Explanation:

a) At the top of the loop, all of the forces point downwards (force of gravity and normal force).

Fnet=ma

ma=m(v^2/R) (centripetal acceleration)

mg=m(v^2/R)

m cancels out (this is why pilot feels weightless) so,

g=(v^2/R)

9.8 m/s^2 = v^2/160 m

v^2=1568 m^2/s^2

v=39.6 m/s

b) At the bottom of the loop, the normal force and the force of gravity point in opposite directions. The normal force is the weight felt.

Convert 300 km/hr to m/s

300 km/hr=83.3 m/s

Convert pilot's weight into mass:

760 N = 77.55 kg

Fnet=ma

n-mg=m(v^2/R)

n=(77.55 kg)(((83.3 m/s)^2)/160 m)+(77.55 kg)(9.8 m/s^2)

n=3363.2 N+760 N=4123 N

5 0
3 years ago
If the kinetic energy of the 40kg box is 784 J, what is the velocity before it strikes the ground?
mamaluj [8]

Answer:

Explanation:

KE=\frac{1}{2}mv^2

784=\frac{1}{2}(40)v^2

784=20v^2

39.2=v^2

v=6.26m/s

4 0
3 years ago
Help!
Evgen [1.6K]

Answer:

factory:

-mechanical energy

-nuclear energy

-gravitational energy

Explanation:

8 0
3 years ago
¿Cuál es el parámetro que indica la cantidad de energía liberada en un movimiento sísmico?
artcher [175]

Answer:

Explanation:

en un movimiento sísmico?

3 0
2 years ago
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