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Zanzabum
3 years ago
11

What is the amount of "stuff in an object?

Physics
2 answers:
ziro4ka [17]3 years ago
7 0

mass is  the amount of "stuff in an object

Andrei [34K]3 years ago
4 0
Good question. The amount of 'stuff' in an object is it's mass. 

A fundamental distinction we learn in physics is the difference between mass and weight. If we were in deep space, away from any very large objects of mass (like a planet), we would be 'weightless' e.g. not feel the effects of gravity, but we would not be 'massless'. Our mass doesn't change based upon our proximity to large objects (gravitational attraction), but the sense of weight does.
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I flow from a warmer object to a cooler object until both objects are the same temperature what am I?
jok3333 [9.3K]

HEAT flows from a warmer object to a cooler object until both objects are the same temperature. The answer is heat!

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4 years ago
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In 2-4 sentences, summarize what you know about EM waves.
MaRussiya [10]

Answer:

In physics, electromagnetic radiation refers to the waves of the electromagnetic field, propagating through space, carrying electromagnetic radiant energy. It includes radio waves, microwaves, infrared, light, ultraviolet, X-rays, and gamma rays.

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3 years ago
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A certain piece of metal (density 9.45 grams per cubic centimeter) has the shape of a hockey puck with a diameter of 13 cm and a
atroni [7]

Answer:

0.0195 m

Explanation:

\rho _{p} = density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³

d_{p} = diameter of hockey puck = 13 cm = 0.13 m

h_{p} = height of hockey puck = 2.8 cm = 0.028 m

\rho _{m} = density of mercury = 13.6 gcm⁻³ = 13600 kgm³

d = depth of puck below surface of mercury

According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck

Weight of mercury displaced = Weight of puck

\rho _{m} (0.25)(\pi d_{p}^{2} d ) g = \rho _{p} (0.25)(\pi d_{p}^{2} h_{p} ) g\\\rho _{m} ( d ) = \rho _{p} ( h_{p} )\\(13600) d = (9450) (0.028)\\d = 0.0195 m

7 0
3 years ago
The closest star to our solar system is Alpha Centauri, which is 4.12 × 10^16 m away. How long would it take light from Alpha Ce
bonufazy [111]

Time = (distance) / (speed)

Time = (4.12x10^16 m) / (3 x10^8 m/s)

Time = 1.37 x 10^8 seconds

Divide the seconds by 86,400 to get days. Then divide the days by 365 to get years.

Time = about 4.35 years

4 0
3 years ago
ANSWER QUICK PLS
vichka [17]

Answer:

what was the answer? Was it 0.98?

7 0
3 years ago
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