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3 years ago

3

Physics

1 answer:

german3 years ago

4 0

Answer:

The time taken by the ship to cover the distance, t = (x/25) s

Explanation:

Given data,

The initial velocity of the ship, u = 20 m/s

The final velocity of the ship, v = 30 m/s

The average velocity of the ship, V = (20 + 30)/ 2

= 25 m/s

The distance covered by the ship, d = x m

Then the time taken by the ship to cover the displacement is,

d = V x t

∴ t = d / V

Substituting the values,

t = x / 25

t = (x/25) s

Hence, the time taken by the ship to cover the distance, t = (x/25) s

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two 200 pound lead balls are separated by a distance 1m. both balls have the same positive charge q. what charge will produce an

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Answer:

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Explanation:

From the question we are told that

The mass of each ball is $m = 200 \ lb = \frac{200}{2.205} = 90.70 \ kg$

The distance of separation is $d = 1 \ m$

Generally the weight of the each ball is mathematically represented as

$W = m * g$

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substituting values

$W = 90.70 * 9.8$

$W = 889 \ N$

Generally the electrostatic force between this balls is mathematically represented as

$F_e = \frac{k * q_1* q_2 }{d^2}$

given that the the charges are equal we have

$q_1= q_2 = q$

$F_e = \frac{k * q^2 }{d^2}$

Now from the question we are told to find the charge when the weight of one ball is equal to the electrostatic force

So we have

$889 = \frac{9*10^9 * q^2}{1^2}$

=> $q = 3.14 *10^{-4} \ C$

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