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rodikova [14]
3 years ago
9

What can you infer about a wave with a long wavelength?

Physics
2 answers:
marta [7]3 years ago
4 0
The answer is high frenquency
katovenus [111]3 years ago
3 0

Answer:

It has a high frequency

Explanation:

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A magnetic field directed along the x-axis changes with time according to B (0.06t2+2.25) T, where t is in seconds. The field is
Gemiola [76]

Answer:

E = 2 \times 10^{-3} V

Explanation:

As we know that rate of change in flux will induce EMF

So here we can

EMF = \frac{d\phi}{dt}

now we have

EMF = \pi r^2\frac{dB}{dt}

now we also know that induced EMF is given by

\int E. dL = \pi r^2\frac{dB}[dt}

E (2\pi r) = \pi r^2\frac{dB}{dt}

E = \frac{r}{2}(\frac{dB}{dt})

now plug in all values in it

E = \frac{0.0133}{2}(0.12 t)

E = 8 \times 10^{-4} (2.50) = 2 \times 10^{-3} V/m

5 0
4 years ago
What is the momentum of the wooden ball after the Collision
Rzqust [24]
Look it up on google copy and paste
7 0
3 years ago
Which of the following simple machines is designed primarily to redirect a force rather than reduce the effort required to move
lys-0071 [83]

Answer:

lever

Explanation:

7 0
3 years ago
Jonah is trying to move his 22-kg desk by pushing on it with a force of 130 N, but his brother is leaning on it with a downward
Dafna11 [192]

Answer:

0.54

Explanation:

Draw a free body diagram.  There are 5 forces on the desk:

Weight force mg pulling down

Applied force 24 N pushing down

Normal force Fn pushing up

Applied force 130 N pushing right

Friction force Fnμ pushing left

Sum of the forces in the y direction:

∑F = ma

Fn − mg − 24 = 0

Fn = mg + 24

Fn = (22)(9.8) + 24

Fn = 240

Sum of the forces in the x direction:

∑F = ma

130 − Fnμ = 0

Fnμ = 130

μ = 130 / Fn

μ = 130 / 240

μ = 0.54

6 0
3 years ago
A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4u2) N, where u is in radians, is applied to t
Soloha48 [4]

A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4θ²) N, where θ is in radians, is applied to the cord, determine the disk’s angular acceleration when it has turned 5 revolutions. The disc has an initial angular velocity \omega _o = 1 \ rad/s and radius from the center of the disc = 300 mm

Answer:

the angular acceleration = 205.706 rad/sec²

Explanation:

GIVEN THAT:

The disc mass = 8 kg

Force = \dfrac{1}{4} \ \ \theta ^2* N

We are told that the given θ is in radians; Therefore; the when it has turned 5 revolutions; we have the θ to be:

\theta = 5 rev * (\dfrac{2 \  \pi  * rad}{1 rev}) \\ \\ \theta = 10 \ \pi \ rad

Also;

the initial angular velocity \omega _o = 1 \ rad/s

radius from the center of the disc = 300 mm = 0.3 m

Thus; the mass moment about the Inertia can be determined via the following expression;

I_o = \dfrac{1}{2}*m*r^2

I_o = \dfrac{1}{2}*8*0.3^2

I_o = 0.36 \ kg/m^3

Now to calculate the angular acceleration; we equate the sum of the moments acting on the Inertia;

SO:

\sum M_o = I_o \alpha

F*0.3 = 0.36* \alpha

\dfrac{1}{2}* \theta^2 *0.3 = 0.36* \alpha

\alpha = 0.20836 \  \theta^2 \ rad/sec^2

\alpha = 0.20836 \  (10 \ \pi )^2 \ rad/sec^2

\alpha = 205.706 \ rad/sec^2

Hence; the angular acceleration = 205.706 rad/sec²

6 0
3 years ago
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