Answer: We can calculate it with the radioactive half life equation
Explanation:
If we already know the initial amount of radioactive material and its half life, we can leave that material for a specific known time and then measure how much of the material is left (since it follows the radioactive deacay) and use the results in the following formula:
Where:
is the final amount of the material
is the initial amount of the material
is the time elapsed
is the half life of the radioactive compound
1. the energy of the wave, 2.the type of medium. 3.the amplitude of the wave. 4.the type of wave
Answer:
Part A
it would take 6 sec
it would take 3 sec
Explanation:
We are told that the power supplied to the wheel is constant which means that the sport car is gaining energy i.e
Hence if power is constantly supplied energy constantly increase
From the formula of the Kinetic energy
we can see that as the speed doubles from 29 mph to 58 mph the energy needed is 
= 4 times of the energy from the formula
Also the time needed would also be 4 times because energy i directly proportional to time
Hence to reach 58mph the time that it would take is
= 
We are told that the ground pushes the car with a constant force and
F = ma
this means that the acceleration is also constant
now from newtons law
v = u +at
Looking at it we see that final velocity is directly proportional with time
hence it would take twice the time to reach twice the final velocity
Time to reach 58mph = 3 s
since time to reach 29 mph(![\frac{1}{2} \ of \ [58mph]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5C%20of%20%5C%20%5B58mph%5D)
) =( 
)1.5 s
Becasue when you rubbed your hair while you were putting on your sweater it caused it to rub against together causing electricity thingy lol. and thats why your hair goes straigh tup.
Answer:
the speed of the first spacecraft as viewed from the second spacecraft is 0.95c
Explanation:
Given that;
speed of the first spacecraft from earth v
= 0.80c
speed of the second spacecraft from earth v
= -0.60 c
Using the formula for relative motion in relativistic mechanics
u' = ( v - v ) / ( 1 - (vv / c²) )
we substitute
u' = ( 0.80c - ( -0.60c) ) / ( 1 - ( ( 0.80c × -0.60c) / c² ) )
u' = ( 0.80c + 0.60c ) / ( 1 - ( -0.48c² / c² ) )
u' = 1.4c / ( 1 - ( -0.48 ) )
u' = 1.4c / ( 1 + 0.48 )
u' = 1.4c / 1.48
u' = 0.9459c ≈ 0.95c { two decimal places }
Therefore, the speed of the first spacecraft as viewed from the second spacecraft is 0.95c
