Answer:
C) all chinchilla
Explanation:
As we know that dominance of alleles for the coat color in rabbits goes like this:
C+ > Cch > Ch > C.
- The allele for full colour or agouti is designated as C+.
- Allele for mutant coat color silvery- gray coat-chinchilla is Cch.
- Allele for “Himalayan” coat is called ‘Ch
- Albino rabbits have whole white coat and allele for this is c
If we cross homozygous chinchilla with homozygous chinchilla the cross will look like this:
P1: chinchilla x chinchilla
P1: Cch Cch X Cch Cch
F1: Cch Cch : Cch Cch
Since all offspring have Cch Cchgenotype that is foe chinchilla phenotype it means that all the offspring will have chinchilla phenotype that makes option C correct.
Hope it help
Answer:
CH4 has one carbon atom and 4 hydrogens, making a total of 5. MgO has 1 magnesium atom and 1 oxygen atom, making for a total of 2.
1.
where in a population:
p - the frequency of the <em>A</em> allele
q - the frequency of the <em>a</em> allele
- the frequency of the <em>AA</em> homozygous genotype
- the frequency of the <em>aa</em> homozygous genotype
2pq - the frequency of the <em>Aa</em> heterozygous genotype
A population at equilibrium will have the sum of all the alleles at the locus equal to 1.
2. Conditions:
A. The breeding population must be large
B. No natural selection
C. The mating must occur randomly
D. No mutations to cause changes in allelic frequency.
E. No changes in allelic frequency due to immigration or emigration.
3. By comparing the actual genetic structure of a population with what we would expect from a Hardy-Weinberg equilibrium, we can determine how much it deviates from the baseline provided by the mathematical model. Depending on how large the deviation is, one or more of the model's assumptions are being violated. Thus, we can attempt to determine which one.
<span>Answer: mycologist []</span>