27. A 0.150 kg baseball is thrown upward with an initial
1 answer:
Answer:
a.
b.
Explanation:
Given:
Mass of the baseball =
The initial velocity of the baseball = 20m/s
The force acting on the baseball is only due to gravity and the air resistance is negligible. The baseball acceleration is constant due to gravity.
According to Newton's second law:
----------(1)
where mass of the baseball
Put all the value in equation 1.
Therefore, the force on the ball when it reaches half of its maximum height is .
Similarly, the force acting on the ball when its peak .
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The change in mechanical energy caused by the dissipative resistance force is equal to, difference between the potential energy and kinetic energy of the object.
Potential energy of the object, P.E = mgh
m is mass of the object = 10 kg
g is acceleration due to gravity = 9.8 m/s²
h= height from which it is dropped =50 m
Substituting the value we get,
P.E = 10×9.8×50 = 4900 J
Kinetic energy of the object, K.E =
v is the velocity of the object = 26 m/s²
K.E = (1/2)×10×(26)²
= 3380 J
Change in mechanical energy caused by dissipative force = P.E ₋ K.E
= 4900 ₋ 3380 = 1520 J