Question

27. A 0.150 kg baseball is thrown upward with an initial

Answer 1

Answer:

a. $1.47N$

b. $1.47N$

Explanation:

Given:

Mass of the baseball = $0.150kg$

The initial velocity of the baseball = 20m/s

The force acting on the baseball is only due to gravity and the air resistance is negligible. The baseball acceleration is constant due to gravity.

According to Newton's second law:

$F_{w} =mg$----------(1)

where mass of the baseball $m = 0.150kgAnd acceleration due to gravity [tex]g = 9.8m/s^{2}$

Put all the value in equation 1.

$F_{w} =0.150\times -9.8$

$F_{w} =-1.47N$

Therefore, the force on the ball when it reaches half of its maximum height is $1.47N$.

Similarly, the force acting on the ball when its peak $1.47N$.