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mr_godi [17]
3 years ago
7

27. A 0.150 kg baseball is thrown upward with an initial

Physics
1 answer:
Tema [17]3 years ago
4 0

Answer:

a. 1.47N

b. 1.47N

Explanation:

Given:

Mass of the baseball = 0.150kg

The initial velocity of the baseball = 20m/s

The force acting on the baseball is only due to gravity and the air resistance is negligible. The baseball acceleration is constant due to gravity.

According to Newton's second law:

F_{w} =mg----------(1)

where mass of the baseball m = 0.150kgAnd acceleration due to gravity [tex]g = 9.8m/s^{2}

Put all the value in equation 1.

F_{w} =0.150\times -9.8

F_{w} =-1.47N

Therefore, the force on the ball when it reaches half of its maximum height is 1.47N.

Similarly, the force acting on the ball when its peak 1.47N.

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Answer:

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                  = [\frac{2t^2}{2} + \frac{t^4}{4}] \left\{ 2} \atop {0}} \right.

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