Lindsay should fly the plane in the direction [W 12.5° S] to get Hamilton.
Using Sine rule to solve this question
Sine rule => SinA/a = SinB/b = SinC/c = constant
The magnitude of wind is 50 with an angle of 60 degrees.
The magnitude of plane is 200 and the angle at which it should fly is unknown and should be θ.
One side is 50 km/hr at an angle of 60 degrees.
sin 60°/200 = sin θ / 50
50 × sin 60° = 200 × sin θ
√3/2 = 4 × sin θ
√3/8 = sin θ
sin θ = 0.2165
θ = sin⁻¹(0.2165)
θ = 12.5°
So Lindsay have to fly the plane in the direction of [W 12.5° S].
Learn more about Sine Rule here:
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Answer:
Explanation:
The magnitude of the magnetic force on the proton is given by:
where:
is the proton charge
is the proton velocity
is the magnetic field
is the angle between the direction of v and B
Substituting into the formula, we find
Answer:
(a) Frequency will be 0.168 Hz
(b) Frequency will be 0.0789 Hz
Explanation:
(a) We have given velocity of the ocean waves in east direction v = 3.2 m /sec
Distance between the crest 
We know that 
So 
(b)Velocity of the ocean waves in westward direction v = 1.5 m /sec
Distance between the crest
We know that
So 
Harmonics, Loop and Harmonic number
Hope this helps :)
