A 65-N box rest on a perfectly smooth surface. The minimum force needed to start the box moving is

1 answer:

7 0

when you say "perfectly smooth", I understand that to mean there's no friction. If that's true, then ANY net horizontal force acting on the box makes it start moving. (D) Naturally, the greater the force is, the faster the box speeds up. That's because F = m A .

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What is the electric potential energy of a charge that experiences a force of 3.6 x 10^-4N when it is 9.8 x 10^-5 from the sourc

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The electric potential energy of the charge is equal to the potential at the location of the charge, V, times the charge, q:
$U=qV$
The potential is given by the magnitude of the electric field, E, times the distance, d:
$V=Ed$
So we have
$U=qEd$ (1)
However, the electric field is equal to the electrical force F divided by the charge q:
$E= \frac{F}{q}$
Therefore (1) becomes
$U=Fd$
And if we use the data of the problem, we can calculate the electrical potential energy of the charge:
$U=Fd=(3.6 \cdot 10^{-4}N)(9.8 \cdot 10^{-5} m)=3.53 \cdot 10^{-8} J$

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Answer:

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