Geometric Shape Tools
Hope this helps :)
Answer:
Options: 1, 3, 5, 7, 8
Explanation:
In steady state at the point when the current at each point in the circuit is
consistent (doesn't change with time).
- In numerous viable circuits, the steady state is accomplished in a brief period of time.
-
In the steady state, the charge (or current) streaming into any point in the circuit needs to equivalent the charge (or current) streaming out which is Kirchhoff's Node or Current law.
Answer:
200 K
Explanation:
0 °C = 273 K
-73°C = 273 K - 73 K = 200 K
If the acceleration is constant (negative or positive) the instantaneous acceleration cannot be
Average acceleration: [final velocity - initial velocity ] /Δ time
Instantaneous acceleration = d V / dt =slope of the velocity vs t graph
If acceleration is increasing, the slope of the curve at one moment will be higher than the average acceleration.
If acceleration is decreasing, the slope of the curve at one moment will be lower than the average acceleration.
If acceleration is constant, the acceleration at any moment is the same, then only at constant accelerations, the instantaneuos acceleration is the same than the average acceleration.
Constant zero acceleration is a particular case of constant acceleration, so at constant zero acceleration the instantaneous accelerations is the same than the average acceleration: zero. But, it is not true that only at zero acceleration the instantaneous acceleration is equal than the average acceleration.
That is why the only true option and the answer is the option D. only at constant accelerations.
Answer:
q = 224 mm, h ’= - 98 mm, real imagen
Explanation:
For this exercise let's use the constructor equation
where f is the focal length, p and q are the distance to the object and the image respectively.
In a mirror the focal length is
f = R / 2
indicate us radius of curvature is equal to the diameter of the eye
R = 3,50 10² mm
f = 3.50 10² /2 = 1.75 10² mm
they also say that the distance to the object is p = 0.800 10³ mm
1 / q = 1 / f - 1 / p
1 / q = 1 / 175 - 1 /800
1 / q = 0.004464
q = 224 mm
to calculate the size let's use the magnification ratio
m = 
h '= 
h ’= - 224 350 / 800
h ’= - 98 mm
in concave mirrors the image is real.
