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Sav [38]
3 years ago
12

An airplane flies 12 m/s due north with a velocity of 35.11 m/s. how far east does it fly?

Physics
2 answers:
Xelga [282]3 years ago
4 0
<span>The question says: The airplane flew due north for the given duration  (i interpret m/s to be milliseconds) and at the given velocity.

 The statement mentions no change in direction or angle, therefore the airplane does not fly east (or the airplane travels 0.0m east).</span>
goblinko [34]3 years ago
3 0
The plane's velocity of 35.11 m/s is actually due in a north-eastward direction. The 12 m/s velocity is the vertical component of the plane's velocity, hence it is pointing northwards. We will use the formula:

Vy = Vsin∅

To determine the angle ∅ at which the plane is flying. This is:

12 = 35.11 * sin∅
∅ = 20.0 degrees

The eastward velocity is:

Vx = Vcos∅
Vx = 35.11 * cos(20)
Vx = 33.0 m/s

The plane's eastward velocity is 33.0 m/s
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C.  The force is a constant change,  because her position on the Ferris wheel will constantly change.  I believe this is the answer, but use sources to double check.  I might use different vocab. then your teachers.  

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Which is a freshwater region characterized as a large standing body of water? A. lake B. river C. ocean D. stream
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A particle of charge 2.0 x 10^-8C experiences an upward force of magnitude 4.0 x10^-6 when it is placed in a particular point in
koban [17]

Answer:

a) The electric field at that point is 2.0\times 10^{2} newtons per coulomb.

b) The electric force is 2.0\times 10^{-6} newtons.

Explanation:

a) Let suppose that electric field is uniform, then the following electric field can be applied:

E = \frac{F_{e}}{q} (1)

Where:

E - Electric field, measured in newtons per coulomb.

F_{e} - Electric force, measured in newtons.

q - Electric charge, measured in coulombs.

If we know that F_{e} = 4.0\times 10^{-6}\,N and q = 2.0\times 10^{-8}\,C, then the electric field at that point is:

E = \frac{4.0\times 10^{-6}\,N}{2.0\times 10^{-8}\,C}

E = 2.0\times 10^{2}\,\frac{N}{C}

The electric field at that point is 2.0\times 10^{2} newtons per coulomb.

b) If we know that E = 2.0\times 10^{2}\,\frac{N}{C} and q = 1.0\times 10^{-8}\,C, then the electric force is:

F_{e} = E\cdot q

F_{e} = \left(2.0\times 10^{2}\,\frac{N}{C} \right)\cdot (1.0\times 10^{-8}\,C)

F_{e} = 2.0\times 10^{-6}\,N

The electric force is 2.0\times 10^{-6} newtons.

7 0
3 years ago
What is acceleration produced by a force of 12 newton exerted on an object of mass 3kg​
jarptica [38.1K]

Answer:

a=F/m

a=12N/3kg  (here newton can be written as kgm/s^2 so kg will be cancelled)

a=4m/s^2

Explanation:

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1. What force is needed to accelerate the stone of
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Answer:

i think its a

Explanation:

and next is 4

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