3 years ago

Which condition must exist in order for conduction to occur between two substances

1 answer:

6 0

Heat!!!!!!!!!!!!!!!!!!! sorry about the exclamation marks but it wont let me post in less it has more than 20 characteristics

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Which cell responds most strongly to a stimulus moving perpendicular to its axis??

AlladinOne [14]

Complex cells are the types of cells that respond most strongly to a stimulus moving perpendicular to its axis.

This is because like simple cell, a complex cell will respond primarily to oriented edges and rating but it has a specific degree of spatial variance. This means its own receptive field cannot be mapped into fixed excitatory and inhiborty zone. Rather, it will respond to patterns of light in a specific orientation within a large field of reception, regardless of its location. Some of these complex cells respond optimally only to a movement in a certain or specific direction.

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3 years ago

A small hole is made at the bottom of a plastic cup. If it is filled with water and allowed to fall freely, will waterfall down

Alex_Xolod [135]

Answer:

Yes, because of both gravity and the fact that nothing is obstructing the hole.

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3 years ago

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2 years ago

How would you find the horizontal net force for the free body diagram below

tiny-mole [99]

Answer:

Add Ff from Fa

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Fnet = sum of all force

horizontal net force = Ff + Fa

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2 years ago

Calculate the force of gravity on the 0.60- kg mass if it were 1.3×107 m above Earth's surface (that is, if it were three Earth

nignag [31]

The gravitational force between two objects is given by:
$F=G \frac{m_1 m_2}{r^2}$
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation

In this problem, the first object has a mass of $m_1=0.60 kg$ , while the second "object" is the Earth, with mass $m_2=5.97 \cdot 10^{24}kg$ . The distance of the object from the Earth's center is $r=1.3 \cdot 10^7 m$ ; if we substitute these numbers into the equation, we find the force of gravity exerted by the Earth on the mass of 0.60 kg:
$F=G \frac{m_1m_2}{r^2}=(6.67\cdot 10^{-11}) \frac{(0.60 kg)(5.97 \cdot 10^{24} kg)}{(1.3 \cdot 10^7 m)^2}= 1.41 N$

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3 years ago