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professor190 [17]
4 years ago
12

Which equation(s) represent joint variations?

Mathematics
2 answers:
Helen [10]4 years ago
8 0

Answer- It's the last two, D & E

Step-by-step explanation:

ale4655 [162]4 years ago
4 0

Answer:

d and e

Step-by-step explanation:

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Which property can be used to solve the equation?
Andrew [12]

Answer:

Division property of equality

Step-by-step explanation:

If you have an equation with the variable not equal to one you want it to equal one so you would divide to get the variable to 1 so 5/5 and then you would do the same to the other side(75/5) d=15.

8 0
2 years ago
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Consider triangle ABC.
shusha [124]
Give me a second to get the answer and I’ll text you back
8 0
3 years ago
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Solve for sin3theta​
aniked [119]

Answer:

 sin 3 θ  = 3 sin θ  - 4 sin³θ

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given    sin 3 θ  

            =  sin ( 2θ + θ )

apply trigonometric formula

       <em>  sin ( A + B) = sin A cos B + cos A sin B </em>

<em>         sin 2 A = 2 sin A cos B</em>

<em>         Cos 2 A = 1 - 2 sin² A </em>

<em>         cos ² A - sin ² A = 1</em>

<u><em>Step(ii):</em></u>-

    sin 3 θ  =     sin ( 2θ + θ )

               =  sin 2θ cosθ +  cos2θ sin θ

              = 2 sin θ cos θ cos θ +( 1 - 2 sin² θ )sin θ

              = 2 sin θ (cos² θ ) + sin θ- 2 sin³ θ

              = 2 sin θ ( 1- sin²θ) + sin θ- 2 sin³ θ

              = 2 sin θ - 2sin³θ +  sin θ- 2 sin³ θ

              = 3 sin θ  - 4 sin³θ

<u><em>Final answer</em></u> :-

 sin 3 θ  = 3 sin θ  - 4 sin³θ

                             

6 0
3 years ago
Tracy can download 24 songs in 10 minutes. At this rate, how many songs can she download in half an hour?
Paul [167]

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3 years ago
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For a group of 100 people, compute(a) the expected number of days of the year that are birthdays of exactly 3 people.(b) the exp
Scilla [17]

Answer:

Step-by-step explanation:

Leaving leap years, a year contains 365 days.

For a group of 100 people, each person is independent of the other and probability of any day being his birthday has a chance of

\frac{1}{365}

a) Probability that  exactly 3 people have same birthday = \frac{1}{365^3}

Each day is independent of the other

And hence no of days having exactly 3 persons birthday out of 100 persons is binomial with n = 365 and p = \frac{1}{365^3}

Expected value of days = np = \frac{1}{365^2}

b) Distinct birthdays is binomail with p =1/365 and n = 365

Hence

expected value = np =1

4 0
4 years ago
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