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3 years ago

Write the equation of the line that passes through the points (-7, 7) and (-6, -5).

Mathematics

1 answer:

defon3 years ago

4 0

Answer:

y = -12x - 77

Step-by-step explanation:

The standard form of the equation is expressed as y = mx+b

m is the slope

Given the coordinate (-7, 7) and (-6, -5).

m = -5-7/-6+7

m = -12/1

m = -12

Get the intercept b

Substitute m= -12 and (-7 7) into y = mx+b

7 = -12(-7) + b

7 = 84 + b

b = 7 - 84

b = -77

Get the required equation

y = mx+b

y = -12x +(-77)

y = -12x - 77

This gives the required equation

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yKpoI14uk [10]

Answer:

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3 years ago

⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden

fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = $\frac{354}{1219}$

n = sample of US adults = 1291

p = population proportion of adults

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

significance level are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]

= [ $\frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ , $\frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ ]

= [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0

3 years ago

Q # 11 please help to resolve

Fofino [41]

It is the fourth choice - 1/4.

There are five odd number out of the ten number they are choosing from.
The probability that Jason will choose an odd number is 5/10 = 1/2
The probability that Kyle will choose an odd number is 5/10 = 1/2
Multiply the two probabilities to get the probability of them choosing odd numbers.
1/2 * 1/2 = 1/4

3 0

3 years ago

Read 2 more answers

sheldon bought 4 1/2 kg of plant food. he uses 1 2/3 kg on his strawberry plant and used 1/4 kg for his tomato plant. how many k

fenix001 [56]

Answer:

Sheldon have left $2\frac{7}{12}\ kg$ of food.