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Gnesinka [82]
2 years ago
9

Write the equation of the line that passes through the points (-7, 7) and (-6, -5).

Mathematics
1 answer:
defon2 years ago
4 0

Answer:

y = -12x - 77

Step-by-step explanation:

The standard form of the equation is expressed as y = mx+b

m is the slope

Given the coordinate (-7, 7) and (-6, -5).

m = -5-7/-6+7

m = -12/1

m = -12

Get the intercept b

Substitute m= -12 and (-7 7) into y = mx+b

7 = -12(-7) + b

7 = 84 + b

b = 7 - 84

b = -77

Get the required equation

y = mx+b

y = -12x +(-77)

y = -12x - 77

This gives the required equation

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5 0
3 years ago
If ON = MN, find MN.
Furkat [3]
Use Pythagorean theorem.

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Answer: |MN| = 4√2.
4 0
3 years ago
Please help with the question above :)!!! ^^
zhannawk [14.2K]
(-1,-9) because if we substituted 1 into x y would be 9 and if we substituted 1/2 into x y would be 3 but if we substituted -1 into x y would be 1/9 so therefore that value is incorrect

7 0
3 years ago
In ΔCDE, the measure of ∠E=90°, the measure of ∠C=70°, and DE = 12 feet. Find the length of CD to the nearest tenth of a foot
Radda [10]

Answer:

CD = 4.4ft

Step-by-step explanation:

Given

DE = 12

\angle C = 70^\circ

Required

Find CD

This question is represented with the attached triangle

To solve CD, we make use of tan formula.

tan(70) = \frac{DE}{CD}

Substitute 12 for DE

tan(70) = \frac{12}{CD}

Make CD the subject

CD = \frac{12}{tan(70)}

CD = \frac{12}{2.7475}

CD = 4.4ft --- approximated

6 0
2 years ago
Read 2 more answers
If $10,000 is invested at an annual rate of 11%, compounded quarterly, find the value of the investment after the given number o
lana [24]

Answer:

a) A\simeq17204.28

b) A\simeq29598.74

c)A\simeq50922.51

Step-by-step explanation:

The amount formula in compound interest is:

A=P(1+\frac{r}{n} )^{nt}

where:

P = principal amount

r = annual interest

n = number of compounding periods

t = number of years

We already know that:

P = $10000

r = 11\% = \frac{11\%}{100\%}=0.11

n = 4 (quarterly in a year)

a ) t = 5 years

A=10000(1+\frac{0.11}{4} )^{(4)(5)}\\\\A=10000(1+\frac{0.11}{4} )^{20}\\\\A=17204.28431\\\\A\simeq17204.28

b) t = 10 years

A=10000(1+\frac{0.11}{4} )^{(4)(10)}\\\\A=10000(1+\frac{0.11}{4} )^{40}\\\\A=29598.73987\\\\A\simeq29598.74

c) t = 15 years

A=10000(1+\frac{0.11}{4} )^{(4)(15)}\\\\A=10000(1+\frac{0.11}{4} )^{60}\\\\A=50922.51361\\\\A\simeq50922.51

5 0
2 years ago
Read 2 more answers
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