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sdas [7]
3 years ago
9

Read the instructions on top and answer 7,8,9, and 10. You will get 10 points. If you do not answer it properly you will be repo

rted.

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

lol u acc reported haha

Step-by-step explanation:

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Given m||n, find the value of x.<br> +<br> 104<br> Answer:
bearhunter [10]

Answer:

x = 104° because they are alternate interior angles and alternate interior angles are equal

Step-by-step explanation:

4 0
2 years ago
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Can anyone rewrite the quadratic function in standard form?
ycow [4]

Answer:

So we first open multiply the parenthesis by 9. 9x+5 is what it is. Now we need to simply it even more with the 2 parenthesis

(9x+5)(x+1) = 9x^2+9x+5x+5 = 9x^2+14x+5

<h2><u>Answer: 9x^2+14x+5</u></h2>

3 0
2 years ago
Good morning my name is Makayla and I'm new so if u can help with my homework I can give u 5 stars if u can help me plss
Leokris [45]

Answer:

7.) 26

8.) 16

9.) 14

10.) 27

Step-by-step explanation:

4 0
3 years ago
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Plz help this is my last math question I need help with!​
charle [14.2K]

Answer:

He buys 8 desks and 6 chairs can i have branliest

Step-by-step explanation:

Set up a system of equations

desks = y chairs = x

x+y=14

125x + 515y = 4870

Eliminate,

-125x -125y = -1750

125x + 515 y = 4870

390 y = 3120

y = 8

substitute in 8

x + 8 = 14

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8 0
3 years ago
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Evalute costheta if sintheta = (sqrt5)/3
torisob [31]

Answer:

\large\boxed{\cos\theta=\pm\dfrac{2}{3}}

Step-by-step explanation:

Use \sin^2x+\cos^2x=1.

We have

\sin\theta=\dfrac{\sqrt5}{3}

Substitute:

\left(\dfrac{\sqrt5}{3}\right)^2+\cos^2\theta=1\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(\sqrt5)^2}{3^2}+\cos^2\theta=1\qquad\text{use}\ (\sqrt{a})^2=a\\\\\dfrac{5}{9}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{5}{9}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{9}{9}-\dfrac{5}{9}\\\\\cos^2\theta=\dfrac{4}{9}\to \cos\theta=\pm\sqrt{\dfrac{4}{9}}\\\\\cos\theta=\pm\dfrac{\sqrt4}{\sqrt9}\\\\\cos\theta=\pm\dfrac{2}{3}

3 0
3 years ago
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