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mylen [45]
3 years ago
5

Assume that the function f is a one-to-one function.

Mathematics
1 answer:
ruslelena [56]3 years ago
4 0

Answer:

Assuming that the function f is a one-to-one function;

If f(3)=4, then f^-1(4) = 3

If f^-1(-8) = -9, then f(-9) = -8

Step-by-step explanation:

A function in which every value in the domain corresponds to exactly one value in the range is said to be a one-to-one function and it passes both the vertical and the horizontal line tests.

If a point (a,b) belongs to a one-to-one function f, the the point (b,a) belongs to its inverse.

In the first case we had f(3)=4 implying that the point (3,4) belongs to f and thus the point (4,3) will belong to the inverse of f. Thus, f^-1(4) = 3

Similarly, if f^-1(-8) = -9 the point (-8,-9) belongs to the inverse of f. This implies that the point (-9,-8) will belong to f. Thus, f(-9) = -8

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In a highschool, 2/5 of the boys make up 250 students. how many boys are there in the high school?
stiv31 [10]

Answer:100 boys

Step-by-step explanation:

250 / 5 is 50.

50 x 2 is 100.

3 0
2 years ago
3.<br> QR<br> find the arc length<br> 02.83<br> 021.99<br> O 12.57<br> 0 34.56
jeka94
Your answer should be 12.57
8 0
3 years ago
Count the number of 5-digit numbers (in the decimal system; integers from 10000 to 99999) which are not divisible by 11.
Alexxandr [17]

Answer:

So total number which is not divisible by 11 = 89999-8181 = 81819  

Step-by-step explanation:

We have to find the total numbers which are not divisible by 11 from 10000 to 99999

Total number from 10000 to 99999 = 99999-10000+1=90000

Just after 10000 the number which is divisible by 11 is 10010

And just below 99999 the number which is divisible by 11 is 99990

Using AP formula

T_N=a+(n-1)d, here a is first term, d is common difference and n is number of terms

So 99990=10010+(n-1)11

n-1 = 8180

n= 8181

So total number which is not divisible by 11 = 90000-8181 = 81819

4 0
3 years ago
20.35 - 08.57 - 09.99 ​
rewona [7]
Your answer will be 1.49
7 0
2 years ago
Read 2 more answers
Please help me I’m desperate
Dafna1 [17]

Answer:

<h2>            The first</h2>

Step-by-step explanation:

\frac29x+3>4\frac59\\{}\quad-3\quad-3\\\\\frac29x\ >\ 1\frac59\\\div\frac29\quad \, \div\frac29\\\\x>1\frac59\div\frac29\\\\x>\frac{14}9\times\frac92\\\\x>\frac{7}1\times\frac11\\\\x>7

That means every x wich is greater than 7

4 0
3 years ago
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