Answer:
first option is not true
Explanation:
1 mole = 6.02 × 10²³ particles
C3H8 has 1 mole, so has 6.02 × 10²³ particles
5O2 has 5 moles so 5 × 6.02 × 10²³ = 3.01 × 10²⁴ particles
3CO2 has 3 moles so 3 × 6.02 × 10²³ = 1.806 × 10²⁴ particles
4H2O has 4 moles so 4 × 6.02 × 10²³ = 2.408 × 10²⁴ particles
Reaction of Elemental Calcium with Water is as follow,
Ca + 2 H₂O → Ca(OH)₂ + H₂↑
When Sodium Metal is reacted with Water it produces NaOH and eliminates Hydrogen gas as shown in following equation,
2 Na + 2 H₂O → 2 NaOH + H₂↑
In both cases corresponding Hydroxides along with Hydrogen gas is produced.
Oxygen is gas. It has 2 O atoms. Atomic mass of 1 O atom is 16 amu. So molecular mass of O2 = 2 x 16 = 32 amu.
Now, mass of 6.023 x 10 ^23 = 32 amu.
Therefore mass of 3.01 x 10^23 = 32 x 3.01 x 10^23 / 6.023 x 10 ^23 = 15.99
= ~16 gm
Answer:
0,72 moles of SO₂ remain
Explanation:
The reaction is:
2SO₂ + O₂ → 2SO₃
Where molecular mass of SO₂ is 64,066g/mol and of SO₃ is 80,066g/mol.
86,0g of SO₂ are:
86,0g × (1mol / 64,066g) = <em>1,34 moles of SO₂</em>.
50,0g of SO₃ are:
50,0g × (1mol / 80,066g) = <em>0,62 moles of SO₃</em>.
Now, as 2 moles of SO₂ produce 2 moles of SO₃, the moles of SO₂ that remain after the reaction are the initial moles of SO₂ - moles of SO₃:
1,34 moles - 0,62 moles =
<em>0,72 moles of SO₂ remain</em>
I hope it helps!
