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fredd [130]
3 years ago
13

KBr(aq) + NaCl(aq) =

Chemistry
1 answer:
torisob [31]3 years ago
7 0
It’s ionic
KCl(at)
Potassium chloride
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You would know you were in the troposphere If?
lora16 [44]
It were raining on you
7 0
3 years ago
Limiting Reactants—————-
denis-greek [22]

Answer:

21.8 grams.

Explanation:

Molar mass data from a modern periodic table:

  • Mg: 24.301;
  • O: 15.999.

How many moles of MgO will be produced if Mg is the limiting reactant?

Number of moles of Mg:

\displaystyle n = \frac{m}{M} = \frac{16.3}{24.301} = 0.670644\;\text{mol}.

The ratio between the coefficient of Mg and that of MgO is 2:2. Two moles of Mg will make two moles of MgO. 0.670644 moles of MgO will be produced if Mg is the limiting reactant.

How many moles of MgO will be produced if O₂ is the limiting reactant?

Number of moles of O₂:

\displaystyle n = \frac{m}{M} = \frac{4.33}{15.999} = 0.270642\;\text{mol}.

The ratio between the coefficient of O₂ and that of MgO is 1:2. One mole of O₂ will make two moles of MgO. 2\times 0.270642 = 0.541284\;\text{mol} of MgO will be produced if O₂ is in excess.

How many moles of MgO will be produced?

0.541284 is smaller than 0.670644. Only 0.541284 moles of MgO will be produced since O₂ will run out before all 16.3 grams of Mg is consumed.

What's the mass of 0.541284 moles of MgO?

Formula mass of MgO:

24.301 + 15.999 = 40.300\;\text{g}\cdot\text{mol}^{-1}.

Mass of 0.541284 moles of MgO:

m = n \cdot M = 0.541284\times 40.300 = 21.8\;\text{g}.

7 0
2 years ago
Which grouping of the three phases of chlorine is listed in order from left to right for increasing distance between chlorine mo
GenaCL600 [577]
Answer:
Solid, Liquid, Gas

Hope it helps! ^^

8 0
3 years ago
Wine goes bad soon after opening because the ethanol ch3ch2oh in it reacts with oxygen gas o2 from the air to form water h2o and
lilavasa [31]
The balanced chemical equation of the reaction described above is,

                            C2H6O + O2 --> H2O  + C2H4O2

If we have 3.84 g of oxygen, we divide by its molar mass.
 
                               n = (3.54 g Oxygen gas) x (1 mole O2/ 32 g O2)
                                 n = 0.11 moles O2

Using ratio and proportion,

               number of moles of ethanol = (0.11 moles O2) x (1 mole C2H6)
                                                  = 0.11 moles C2H6

Then, we multiply the calculated value to its molar mass, 46 grams /mol.
                    mass of ethanol = (0.11 mol) x (46 grams / mol)
                                                = <em>5.06 grams</em>
8 0
3 years ago
3. Mercury is a liquid metal that has a density of 13.58 g/mL. Calculate the volume of mercury
Alona [7]

Answer:

0.03682 mL of mercury

Explanation:

We know the density of the mercury which is 13.58 g/mL

density = mass / volume

volume = mass / density

Now we can calculate the volume of 0.5 g of mercury:

volume = 0.5 / 13.58 = 0.03682 mL of mercury

5 0
3 years ago
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