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Anna35 [415]
3 years ago
14

Consider the four free body diagrams. Free-body diagrams are diagrams used to show the relative magnitude and direction of all f

orces acting upon an object in a given situation. Do any of the free body diagrams indicate motion? If yes, which one(s). Explain.
A)
No. In each case, the forces are balanced.


B)
Yes. In B the book is slowing down because of the friction force opposing motion.


C)
You cannot tell if there is any motion. You can only determine how much force is acting on the objects.


D)
Yes. In B and D. In both cases, there is a net force.
In B, there is a net force to the left; in D there is a net force upward.

Chemistry
2 answers:
Alexeev081 [22]3 years ago
7 0

Answer:

The answer is D

Explanation:

9966 [12]3 years ago
5 0
If you look closely at each of the four diagrams you would be able to conclude that

<span>D) 
Yes. In B and D. In both cases, there is a net force. 
In B, there is a net force to the left; in D there is a net force upward.

In A and C, the forces are in equilibrium both in the horizontal and vertical direction.</span>
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which conversion factor do you use first to calculate the number of grams of fecl3 produced by the reaction of 30.3 g of fe with
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Answer:

30

Explanation:

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Charge can be transfered during electrolysis. Name the type of particle responsible for the transfer of charge in the wire and i
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Electrons are responsible for the transfer of charge.
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3 years ago
What is the limiting reagent when a 2.00 g sample of ammonia is mixed with 4.00 g of oxygen?​
UNO [17]

Answer:

Ammonia is limiting reactant

Amount of oxygen left  = 0.035 mol

Explanation:

Masa of ammonia = 2.00 g

Mass of oxygen = 4.00 g

Which is limiting reactant = ?

Balance chemical equation:

4NH₃ + 3O₂     →     2N₂ + 6H₂O

Number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 2.00 g/ 17 g/mol

Number of moles = 0.12 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 4.00 g/ 32 g/mol

Number of moles = 0.125 mol

Now we will compare the moles of ammonia and oxygen with water and nitrogen.

                      NH₃          :            N₂

                        4             :             2

                      0.12           :           2/4×0.12 = 0.06

                      NH₃         :            H₂O

                        4            :             6

                        0.12       :           6/4×0.12 = 0.18

                       

                       O₂            :            N₂

                        3             :             2

                      0.125        :           2/3×0.125 = 0.08

                        O₂           :            H₂O

                        3              :             6

                        0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                        NH₃          :             O₂

                           4            :              3

                           0.12       :          3/4×0.12= 0.09

Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

3 0
3 years ago
If acid precipitation rain changes the ph of a pond from 7.0 to 5.0, the level of hydrogen ion has changed by a factor of ______
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When pH=7, [H⁺] =10⁻⁷.
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I believe the correct answer is B

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