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jarptica [38.1K]
3 years ago
11

Two gerbils run in place with a linear speed of 0.50 m/s on an exercise wheel that is shaped like a hoop. Find the angular momen

tum of the system if each gerbil has a mass of 0.22 kg and the exercise wheel has a radius of 8 cm and a mass of 4.5 g.
Physics
1 answer:
Brilliant_brown [7]3 years ago
7 0

Answer:

L = 0.018 kg m^2/s

Explanation:

Angular speed and linear speed is related to each other as

v = R\omega

here we know that

v = 0.50 m/s

R = 0.08 m

now we have

\omega = \frac{v}{R}

\omega = \frac{0.50}{0.08}

\omega = 6.25 rad/s

Now we know that moment of inertia of the system is given as

I = (2M + m)R^2 [tex][tex]I = (2\times 0.22 + 0.0045)(0.08)^2

I = 2.84 \times 10^{-3} kg m^2

Now angular momentum of the system is given as

L = I\omega

L = (2.84 \times 10^{-3})(6.25)

L = 0.018 kg m^2/s

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