A. Layer C is the right answer out of all the choices
Answer:
The equilibrium position for the third charge is 69.28 cm
Explanation:
Given;
q₁ = -5.00 x 10⁻⁹ C
q₂ = -2.00 x 10⁻⁹ C
q₃ = 15.00 x 10⁻⁹ C
distance between q₁ and q₂ = 40.0 cm = 0.4 m
(-q₁)--------------------------------------(-q₂)---------------------------------(+q₃)
At equilibrium the repulsive force between q₁ and q₂ must be equal to attractive force between q₂ and q₃
According to Coulomb's law, repulsive or attractive force between charges is calculated as;

where;
F is repulsive or attractive force between charges
K is Coulomb's constant = 8.99 x 10⁹ Nm²/c²
r₁ is the distance between q₁ and q₂
q₁, q₂ and q₃ are the charge
distance between q₂ and q₃, r₂ is calculated as;

Therefore, the equilibrium position for the third charge is 69.28 cm
gravity? I am not completly sure but this is my best guess
Her displacement is 41m. First, she walks 32m to the right, then 12m to the left. I subtract 12 from 32 to get 20m. She walks 28m to the right. Add 28 to 20 and you get 48. Finally, she walks 7m to the left. Subtract 7, then you get 41m.