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Andreas93 [3]
3 years ago
6

Determine whether the statements below are true or false.

Mathematics
1 answer:
AnnZ [28]3 years ago
5 0

Answer:

A

Step-by-step explanation:

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Find the equation of the linear function represented by the table below<br> in slope-intercept form.
Arturiano [62]

Answer:

Equation of a line, y = mx+c

Slope (m)= (Y2-Y1)/(X2-X1), let Y2=7, Y1=3 , X2=2 and X1=1

m=(7-3)/(2-1)

= 4/1

= 4

Picking any value of y and its corresponding x including m, put them into the equation of the line

y=mx+c

3 =4(1)+c

3=4+c

3-4=c

-1=c

y=mx+c

y=4x+(-1)

y=4x-1

8 0
3 years ago
Which expressions are equivalent to 4x^4-9x^2?
weeeeeb [17]
We can cosider this to be  a difference of 2 squares  so 

4x^4 - 9x^2 = (2x^2 - 3x)(2x^2 + 3x)   so D is one answer

also we could take x^2  out and get 
x^2(4x^2 - 9)  = C
3 0
3 years ago
Francine is selling ice cream from her shack on the ocean. She opens the shack
madam [21]

Answer: The answer for that would be 325

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
George and Paula are running around a circular track. George starts at the westernmost point of the track, and Paula starts at t
arsen [322]

Answer:

George is 43.20 ft East of his starting point.

Step-by-step explanation:

Let Paula's speed be x ft/s

George's speed = 9 ft/s

Note that speed = (distance)/(time)

Distance = (speed) × (time)

George takes 50 s to run a lap of the track at a speed of y ft/s

Meaning that the length of the circular track = y × 50 = 50y ft

George and Paula meet 14 seconds after the start of the run.

Distance covered by George in 14 seconds = 9 × 14 = 126 ft

Distance covered by Paula in 14 seconds = y × 14 = 14y ft

But the sum of the distance covered by both runners in the 14 s before they first meet each other is equal to the length of the circular track

That is,

126 + 14y = 50y

50y - 14y = 126

36y = 126

y = (126/36) = 3.5 ft/s.

Hence, Paula's speed = 3.5 ft/s

Length of the circular track = 50y = 50 × 3.5 = 175 ft

So, in 4 minutes (240 s), with George running at 9 ft/s, he would have ran a total distance of

9 × 240 = 2160 ft.

2160 ft around a circular track of length 175 ft, means that George would have ran a total number of laps (2160/175) = 12.343 laps.

Breaking this into 12 laps and 0.343 of a lap from the starting point. 0.343 of a lap = 0.343 × 175 = 60 ft

So, 60 ft along a circular track subtends an angle θ at the centre of the circle.

Length of an arc = (θ/360°) × 2πr

2πr = total length of the circular track = 175

r = (175/2π) = 27.85 ft

Length of an arc = (θ/360) × 2πr

60 = (θ/360°) × 175

(θ/360°) = (60/175) = 0.343

θ = 0.343 × 360° = 123.45°

The image of this incomplete lap is shown in the attached image,

The distance of George from his starting point along the centre of the circular track = (r + a)

But, a can be obtained using trigonometric relations.

Cos 56.55° = (a/r) = (a/27.85)

a = 27.85 cos 56.55° = 15.35 ft

r + a = 27.85 + 15.35 = 43.20 ft.

Hence, George is 43.20 ft East of his starting point.

Hope this Helps!!!

6 0
3 years ago
The taxi cost $2.25 for the first mile plus $.15 Cents for each additional tenth of a mile. For a 5.2-mile trip, Eric paid $10 a
Readme [11.4K]
The driver's tip was $1.45 because the trip cost $8.55 (2.25+1.5+1.5+1.5+1.5+ 0.3) and Eric gave the driver $10 so to find how much the driver got tipped, you need to subtract 8.55 from 10 so $10 - $ 8.55 = $1.45
7 0
3 years ago
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