<span> We are given with the rate constant of a first-order decomposition of n2o which is equal to 3.40 s-1. Half life of the radioactive material can be determined through the formula: t= ln2 /k where t is the half life of the material. t then upon substitution is equal to 0.2048 s. </span>
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Btw idk about the oxides and male ilitt
Answer:
5.8 g of carbon dioxide are produced
Explanation:
The Law of Conservation of Mass states that the mass of the reactants must equal the mass of the products in all chemical reactions.
This is the chemical reaction (combustion)
CH₄ + 2O₂ → CO₂ + 2H₂O
12.2 g 14 g x 20g
Mass in reactants = 12.2 g + 14 g = 26.2 g
Mass in products = x + 20 g
26.2 g = x + 20g
26.2 g - 20g = x
5.8 g = x