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Kryger [21]
3 years ago
9

Nitrogen was heated from 17°C to 37°C. The original volume of nitrogen was 8.5 L. Find the new volume in liters assuming P and n

remain the same.
Chemistry
1 answer:
Nata [24]3 years ago
7 0

Answer:

The new volume of the gas is 9.086 liters.

Explanation:

Let suppose that nitrogen has a behavior of ideal gas, the equation of state for ideal gases is:

P\cdot V = n \cdot R_{u}\cdot T (1)

Where:

P - Pressure, measured in atmospheres.

V - Volumen, measured in liters.

n - Molar amount, measured in moles.

T - Temperature, measured in Kelvin.

R_{u} - Ideal gas constant, measured in atmosphere-liters per mole-Kelvin.

If pressure and molar amount of the gas remain constant, then we construct the following relationship:

\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}} (2)

If we know that T_{1} = 290.15\,K, P_{1} = 8.5\,L and T_{2} = 310.15\,K, then the new volume of the gas is:

V_{2} = \left(\frac{T_{2}}{T_{1}}\right)\cdot V_{1}

V_{2} = \left(\frac{310.15\,K}{290.15\,K} \right)\cdot (8.5\,L)

V_{2} = 9.086\,L

The new volume of the gas is 9.086 liters.

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Is NO ionic or covalent
Effectus [21]
Covalent

A covalent bond is the bond where electrons are shared. This occurs between two non mental. N is nitrogen and O is oxygen, therefore NO would be a bond between two non metals. So it must be covalent.
8 0
3 years ago
1. Unas de las formas de producir nitrógeno gaseoso (N2) es mediante la oxidación de metilamina (CH3NH2), tal como se muestra en
Maslowich

Answer:

a) 4CH₃NH₂ + 9O₂ ⇄  4CO₂ + 10H₂O + 2N₂    

b) m = 5,043 g

c) % = 69,4 %

Explanation:

a) La ecuación balanceada es la siguiente:

4CH₃NH₂ + 9O₂ ⇄  4CO₂ + 10H₂O + 2N₂              

En el balanceo, se tiene en la relación estequiométrica que 4 moles de metilamina reacciona con 9 moles de oxígeno para producir 4 moles de dióxido de carbono, 10 moles de agua y 2 moles de nitrógeno.  

b) Para determinar la masa de nitrógeno se debe calcular primero el reactivo limitante:

n_{O_{2}} = \frac{m}{M} = \frac{25,6 g}{31,99 g/mol} = 0,800 moles      

n_{CH_{3}NH_{2}} = \frac{4}{9}*0,800 moles = 0,356 moles

De la ecuación anterior se tiene que la cantidad de moles de metilamina necesaria para reaccionar con 0,800 moles de oxígeno es 0,356 moles, y la cantidad de moles iniciales de metilamina es 0,5 moles, por lo tanto el reactivo limitante es el oxígeno.

Ahora, podemos calcular la masa de nitrógeno producida:

n_{N_{2}} = \frac{2}{9}*n_{O_{2}} = \frac{2}{9}*0,8 moles = 0,18 moles

m_{N_{2}} = n_{N_{2}}*M = 0,18 moles*28,014 g/mol = 5,043 g

Por lo tanto, se pueden producir 5,043 g de nitrógeno.

c) El redimiento de la reacción se puede calcular usando la siguiente fórmula:

\% = \frac{R_{r}}{R_{T}}*100

<u>Donde</u>:

R_{r}: es el rendimiento real

R_{T}: es el rendimiento teórico

\% = \frac{3,5}{5,043}*100 = 69,4

Entonces, el procentaje de rendimiento de la reacción es 69,4%.

Espero que te sea de utilidad!        

5 0
3 years ago
If an isotope of uranium, uranium-235, has 92 protons, how many protons does the isotope uranium-28 have?
padilas [110]
92. A<span>ll </span>isotopes<span> of uranium have the same number of protons</span>
4 0
3 years ago
Iodine 131, cesium 137, and strontium 90 are all considered isotopes. What are isotopes?
Nitella [24]

Answer:

Isotopes are variants of an element, where the number of neutrons is different but its number of protons stay the same.

Explanation:

If the number of protons had changed then it would just be a different element.

Electron number changing simply adds charge to the atom, and doesn't change it or anything.

PLS GIVE BRAINLIEST

3 0
3 years ago
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In the Atomium building, what do the tubes represent?
Monica [59]

Answer:

74 = celcus

Explanation:

7 0
2 years ago
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