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Zepler [3.9K]
2 years ago
6

An aqueous solution of methanol (MM = 32.04 g/mol) has a molality of 8.83 m and a density of 1.15 g/mL. What is the molarity of

methanol in the solution?
Chemistry
1 answer:
hodyreva [135]2 years ago
7 0

We have that the  the molarity of methanol in the solution is mathematically given as

Morality=7.91mol/l

<h3>Chemical Reaction</h3>

Question Parameters:

An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)

A molality of 8.83 m and a density of 1.15 g/mL.

Generally the equation for the   is mathematically given as

Morality=\frac{moles of solute }{mass of the solvent}

where

Mass of solution=(100+282.2)

Mass of solution=1289.9

Volume=1289.9/1.15

Volume=1.115L

Therefore

Morality=\frac{moles of solute }{mass of the solvent}

Morality=8.83/1.115

Morality=7.91mol/l

For more information on Chemical Reactionvisit

brainly.com/question/11231920

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Answer:

It is important to know if a resource is renewable or non-renewable because renewable resources are self-sustaining (unlike non-renewable resources). If a non-renewable resource is used too often, that resource may eventually become non-existant. This can also happen to renewable resources, but it is more difficult.

3 0
2 years ago
½H2(g) + ½I2(g) → HI(g), ΔH = +6.2 kcal/mole 21.0 kcal/mole + C(s) + 2S(s) → CS2(l) What type of reaction is represented by the
wlad13 [49]

<u>Answer:</u>

Exothermic Reaction are those reaction, in which energy is released while in endothermic reaction are those, in which energy is absorbed.

<u>Explanation:</u>

First Reaction:

As in this reaction, energy is released

½H2(g) + ½I2(g) → HI(g), ΔH = +6.2 kcal/mole

so it is <em>exothermic reaction</em>

Second reaction:

As in this reaction, energy is absorbed

21.0 kcal/mole + C(s) + 2S(s) → CS2(l)

so it is <em>endothermic reactions</em>.


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3 years ago
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*URGENT*
DaniilM [7]

Answer:

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3 years ago
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Please help thank you (15 points)
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Answer:

D. The sun has less gravitational pull on Pluto because it is farther away.

6 0
2 years ago
G. Amount of charge required to reduce
Nady [450]

Answer:

\boxed{\text{c) 4 F}}

Explanation:

1. Write the skeleton equation for the half-reaction

NO₃⁻ ⟶ N₂O

2. Balance all atoms other than H and O

2NO₃⁻ ⟶ N₂O

3. Balance O by adding H₂O molecules to the deficient side.

2NO₃⁻ ⟶ N₂O + 5H₂O

4. Balance H by adding H⁺ ions to the deficient side.

2NO₃⁻ + 10H⁺ ⟶ N₂O + 5H₂O

5. Balance charge by adding electrons to the deficient side.

2NO₃⁻ + 10H⁺ + 8e⁻ ⟶ N₂O + 5H₂O

The amount of charge required to reduce 2 mol of NO₃⁻ is 8 F

\text{The amount of charge required to reduce 1 mol of NO$_{3}^{-}$ is \boxed{\textbf{4 F}}}

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3 years ago
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