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tangare [24]
3 years ago
8

Hydrogen (H) and helium (He) are produced in the core of stars in a process called nuclear fusion. Over time stars begin to prod

uce more complex atoms as protons are added to the nuclei of existing atoms. Which of the following statements does not correctly compare the structures of an atom of hydrogen to an atom of helium?
A. Hydrogen and helium have 1 electron shell or energy level.
B. Helium is a noble gas with 8 valence electrons, while hydrogen has 1 valence electron
C. Helium has 2 protons in its nucleus while hydrogen has only 1 proton in its nucleus
D. Hydrogen has no neutrons while helium has two.
Chemistry
1 answer:
rosijanka [135]3 years ago
4 0
A C and D are all correct, Helium and Hydrogen only have a 1s orbital, and helium has 2 protons, while hydrogen has 1, and finally Hydrogen has no neutrons while helium has 2. Helium does not however have 8 valence electrons as the 1s orbital can only hold 2, meaning B is the “correct” (false) answer.
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How many photons are produced in a laser pulse of 0.497 J at 469 nm?
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<span>E=hν</span> where E is the energy of a single photon, and ν is the frequency of a single photon. We recall that a photon traveling at the speed of light c and a frequency ν will have a wavelength λ given by <span>λ=<span>cν</span></span>λ will have an energy given by <span>E=<span><span>hc</span>λ</span></span><span>λ=657</span> nm. This will be <span>E=<span><span>(6.626×<span>10<span>−34</span></span>)(2.998×<span>108</span>)</span><span>(657×<span>10<span>−9</span></span>)</span></span>=3.0235×<span>10<span>−19</span></span>J</span> So we now know the energy of one photon of wavelength 657 nm. To find out how many photons are in a laser pulse of 0.363 Joules, we simply divide the pulse energy by the photon energy or <span>N=<span><span>E<span>pulse </span></span><span>E<span>photon</span></span></span>=<span>0.363<span>3.0235×<span>10<span>−19</span></span></span></span>=1.2×<span>1018</span></span>So there would be <span>1.2×<span>1018</span></span><span> photons of wavelength 657 nm in a pulse of laser light of energy 0.363 Joules.</span>
7 0
3 years ago
Read 2 more answers
A compound is found to contain 37.32 % phosphorus , 16.88 % nitrogen , and 45.79 % fluorine by
Alla [95]

Answer: 1. The empirical formula is PNF_2  

2. The molecular formula is PNF_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of P = 37.32 g

Mass of N = 16.88 g

Mass of F = 45.79 g

Step 1 : convert given masses into moles.

Moles of P =\frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{37.32g}{31g/mole}=1.20moles

Moles of N =\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.88g}{14g/mole}=1.20moles

Moles of F =\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{45.79g}{19g/mole}=2.41moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For P = \frac{1.20}{1.20}=1

For N = \frac{1.20}{1.20}=1

For F =\frac{2.41}{1.20}=2

The ratio of P: N: F= 1: 1: 2  

Hence the empirical formula is PNF_2

The empirical weight of PNF_2= 1(31)+1(14)+2(19)= 82.98 g.

The molecular weight = 82.98 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{82.98}{82.98}=1

The molecular formula will be=1\times PNF_2=PNF_2

3 0
3 years ago
How many moles of O2 molecules should be supplied to burn 1 mol of CH4 molecules in a domestic furnace?
Sati [7]
The combustion of 1 mole of methane (CH4) in a domestic furnace requires 2 moles of O2 molecules, assuming the combustion was complete or ideal. To solve this problem, use stoichiometry of the reaction's balanced chemical equation:

CH4 + 2O2 --> CO2 + 2H2O

The ratio of CH4 to O2 in terms of moles is 1:2. So 1 mole of CH4 needs 2 moles of O2.
4 0
3 years ago
Is 2H2 + O2=2H2O a balanced equation
Mnenie [13.5K]

Explanation:

Yes, the equation is balanced. There are the same number of Hydrogen (H) and Oxygen (O) atoms on both sides of the equation.

7 0
3 years ago
How many moles of MgCl2 are produced from 4 moles of HCl
Karolina [17]

Answer:

2 moles of MgCl2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Mg + 2HCl —> MgCl2 + H2

Now, we can determine the number of mole MgCl2 produced from 4 moles of HCl as follow:

From the balanced equation above,

2 moles of HCl reacted to produce 1 mole of MgCl2.

Therefore, 4 moles of HCl will react to produce = (4 x 1)/2 = 2 moles of MgCl2.

Therefore, 2 moles of MgCl2 were produced from the reaction of 4 moles of HCl.

5 0
3 years ago
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