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dlinn [17]
3 years ago
12

What is the expected mass (in kg) of a 10 over 5 B isotope? 1 proton = 1.6726 × 10-27 kg 1 neutron = 1.6749 × 10-27 kg A.1.67 ×

10-26 kg B.1.67 × 1026 kg C.2.51 × 10-26 kg D.2.51 × 1026 kg
Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
8 0
^{10}_5 B
An atom of this isotope contains 5 protons and 10-5=5 neutrons.

5 \times 1.6726 \times 10^{-27} + 5 \times 1.6749 \times 10^{-27} = \\
8.363 \times 10^{-27} + 8.3745 \times 10^{-27}= \\
16.7375 \times 10^{-27}= \\
1.67375 \times 10^{-26} \approx \\
1.67 \times 10^{-26}

The answer is A. 1.67 × 10⁻²⁶ kg.
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