1. 3x - 2y = 0 => y = 3/2x
4x + 2y = 14<=> 4x + 2*(3/2x) = 14<=> 7x = 14<=> x = 2 & y = 3
2.3p + q = 7=> q = 7 - 3p
2p - 2q = -6<=> 2p - 2*(7-3p) = -6<=> 2p - 14 + 6p = -6<=> 8p = -6 + 14 = 8<=> p = 1 & q = 4
3.3x - 2y = 1=> x = (1+2y)/3
8x + 3y = 2<=> 8*(1+2y)/3 + 3y = 2<=> 8*(1+2y)/3 - 2 = -3y<=> 3*(8*(1+2y)/3 - 2) = -3*(3y)<=> 8*(1+2y) - 6 = -9y<=> 8 + 16y - 6 = -9y<=> 2 = -25y<=> y = -2/25 & x = 7/25
+1/31 and -1/31
Hope this helps.
Answer:
The expected number of times is 4.
Step-by-step explanation:
Looking at the question, we see that this follows a geometric distribution because it is asking for the expected number of trials hat will bring about the FIRST SUCCESS. The probability of success is
Since it is a geometric distribution, we know that the expected value of a random variable X, E(X) that follows a geometric distribution is given as:
E(X) = 1/p where p is the probability of success.
Therefore, the expected number of times will be
E(X) = 1/(1/p) = 1/(1/4) = 4.
Hence, the expected number of times is 4.
Answer:
x < 3
Step-by-step explanation:
Answer:
0.5
Step-by-step explanation: