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oksian1 [2.3K]
3 years ago
5

The manager of a fashionable restaurant open Wednesday through Saturday says that the restaurant does about 29 percent of its bu

siness on Friday night, 31 percent on Saturday night, and 21 percent on Thursday night. What seasonal relatives would describe this situation?(Round your answers to 2 decimal places.)
Wednesday
Thursday
Friday
Saturday
Mathematics
1 answer:
RideAnS [48]3 years ago
8 0

Answer: The seasonal relatives is calculated are as follows:

Step-by-step explanation:

Given that,

restaurant only open from Wednesday to Saturday,

  • 29 percent of its business on Friday
  • 31 percent on Saturday night
  • 21 percent on Thursday night.

∴ The remaining 19% of its business he does on Wednesday

Now, suppose that total production of sales in a given week be 'y'

So, average sales in a week = \frac{y}{4}

If we assume that y = 1

hence, average sales in a week = \frac{1}{4}

= 0.25

Now, we have to calculate the seasonal relatives,

that is,

=  \frac{Sales in a given day}{average sales in a week}

Wednesday:

= \frac{0.19}{0.25}

= 0.76

Thursday:

= \frac{0.21}{0.25}

= 0.84

Friday:

= \frac{0.29}{0.25}

= 1.16

Saturday:

= \frac{0.31}{0.25}

= 1.24

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Step-by-step explanation:

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3 years ago
A school will offer pizza on Friday's if at least 30% of the students will buy it. A sample of 50 students asked if they would b
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Answer:

0.0614

Step-by-step explanation:

Solution:-

- The school offers pizza on friday when at-least 30% students are willing to buy.

- The minimum required proportion of students, p = 30%

- A sample of n = 50 students were taken and out of the sample x = 10 people responded willing to buy pizza.

- We will denote a random variable X: the number of students willing to buy Pizza on fridays.

- For the sample of n = 50, for Pizza to be offered on friday the expected number of student who should opt for buying must be at-least:

           Expected ( Mean - u ) = n*p = 50*0.3 = 15 people.

- The standard deviation for the normal distribution can be determined as follows:

          standard deviation ( s ) = √n*p*(1-p)

                                                 = √50*0.3*(0.7)

                                                 = √10.5 = 3.2404

- We will assume that the random variable X follows normal distribution:

                       X ~ Norm ( 15 , 3.2404^2 )

- To determine the probability of sample of size n = 50 with proportion or lower. The number of people willing to buy pizza on friday as per survey are x = 10.

- Evaluate the standard normal ( Z-score ):

                      P ( X < x ) = P ( Z < ( x - u ) / s )

                      P ( X < 10 ) = P ( Z < ( 10 - 15 ) / 3.2404 )

                      P ( X < 10 ) = P ( Z < -1.54301 )

- Use the standard normal tables to determine the value of P ( Z < -1.54301 ):

                     P ( X < 10 ) = P ( Z < -1.54301 ) = 0.0614

Answer: The probability of getting a sample with the proportion or lower given a population with a proportion of .30 is 0.0614.

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Answer:

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Step-by-step explanation:

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Answer: The correct option is, The coefficient of the first term.

Step-by-step explanation:

The given function is,

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As, the degree of the polynomial is '3'. So, the leading coefficient will determine the structure of the graph.

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The graph is also shown below.

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