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2 years ago

-2 2/3, -5 1/3, -10 2/3, -21 1/3, -41 2/3 Which formula can be used to describe the sequence?

Mathematics

2 answers:

Gelneren [198K]2 years ago

7 0

Each term is double the one before it, so the appropriate choice is ...

... D. f(x+1) = 2f(x)

Helga [31]2 years ago

6 0

Answer:

(D) f(x+1)=2f(x)

Step-by-step explanation:

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If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

6 0

3 years ago

What's the numerator for the following rational<br> expression?<br> X/y + 3/y= ?/y

Fittoniya [83]

Answer:

x + 3

Step-by-step explanation:

Since we have a common denominator, we can just simply combine the numerator which is just x+3.

7 0

3 years ago

"-3 = 9/5c + 32" help with finding c pls!! i need it as a decimal btw.

Serggg [28]

Answer:

-3=9/5c +32

-3*5c=9/5c*5c+32*5c

-15c=9+160c

-15c -160c =9

c(-15-160)=9

c(-15-160)/(-15-160)=9/(-15-160)

c=9/(-15-160)

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2 years ago

What do diffraction and refraction have

nignag [31]

Answer:

They are both due to the wave nature of light.

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3 years ago

What is the equation of a line with a slope of 3 and a point (3, 1) on the line? Express the equation in the form of y=mx+b wh

Nastasia [14]

The answer is y=3x-8

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3 years ago