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3 years ago

Magnesium (Mg): 1s22s22p63s2 longhand notation noble-gas notation

Chemistry

2 answers:

blsea [12.9K]3 years ago

6 0

Answer: longhand notation

Explanation: I just did it on Edg

Svetradugi [14.3K]3 years ago

4 0

Answer:

longhand notation

Explanation:

i got it right on edge

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Jordan is doing a science fair project on the effects of music on the growth of tomatoes. He has two tomato plants, Plant A and

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The control group is the plant without the music because nothing is being done to it. while the experimental group is the plant with music because you are testing it in a different environment (the music).

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Helium is most likely to behave as an ideal gas when it is under(1) high pressure and high temperature(2) high pressure and low

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Helium is most likely to behave as an ideal gas when it is under 2) High pressure and low temperature.

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4 years ago

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Infrared light from the Sun is detected on Earth as _____.

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Answer: heat

Explanation:

Infrared radiation is popularly known as "heat radiation",[21] but light and electromagnetic waves of any frequency will heat surfaces that absorb them. Infrared light from the Sun accounts for 49%[22] of the heating of Earth, with the rest being caused by visible light that is absorbed then re-radiated at longer wavelengths

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4 years ago

The fire department needs information on friction losses occurring between a water main and an open fire hydrant. At maximum mai

lisov135 [29]

Explanation:

The given data is as follows.

$P_{1}$ = 85 psig, $P_{2}$ = $P_{atm}$ = 15 psia

Q = 1620 gpm, d = 2.5 inch, l = 8 ft = 2.4384 m

According to Darey-Weisbach equation,

$h_{l} = \frac{4fl \nu^{2}}{2gD}$ ......... (1)

Value of 'f' will be decided on the basis of Reynold number.

As, it is known that $R_{l} = \frac{\rho \nu d}{\mu}$

where, $\mu_{water}$ = $10^{-3}$ kg/ms

As it is known that 1 gpm = $\frac{1}{3.67} m^{3}/hr$

So, $1 m^{3}/hr$ = 3.67 gpm

Therefore, Q = $1620 \times \frac{1}{3.67}$

= $441.4168 m^{3}/hr$

= 0.1226 $m^{3}/s$

In, 1 inch = 2.54 cm = 0.0254 m

Therefore, d = 2.5 \times 0.0254 = 0.0635 m

V = $\frac{Q}{\frac{\pi}{4}d^{2}}$

= $\frac{0.1226}{0.785 \times (0.0635)^{2}}$

= 38.73 m/s

Hence, we will calculate Reynold number as follows.

$R_{l}$ = $\frac{1000 \times 38.73 \times 0.0635}{10^{-3}}$

= 2459355

As $R_{l}$ > 2000 then, it means that flow is turbulent.

As, f = 0.079 $R^{-0.25}_{l}$

= 0.001994

Putting all the values into equation (1) formula as follows.

$h_{l} = \frac{4fl \nu^{2}}{2gD}$

= $\frac{4 \times 0.001994 \times 2.4384 \times (38.73)^{2}}{2 \times 9.81 \times 0.0635}$

= $1.04069 \times 10^{5} m$

Thus, we can conclude that friction loss from the main to the discharge point is $1.04069 \times 10^{5} m$ .

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3 years ago

Explain what is the difference between bohr and rutherford atomic models

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Answer:

The Rutherford Model shows an atom with electrons orbiting a fixed, positively charged nucleus in set, predictable paths. The Bohr model shows electrons travel in defined circular orbits around the nucleus.

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