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2 years ago

In the compound aluminum oxide, which is the cation?

Chemistry

1 answer:

8090 [49]2 years ago

7 0

Answer:

-Aluminum Oxide: The cation is Al3+ and the anion is O2-. The sum of the charges for aluminum oxide is 2(3+) + 3(2-) = 0. Thus, the formula is Al2O3. An ionic compound is named using the name of the cation followed by the name of the anion, eliminating the word ion from each.

Explanation:

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Particle Mass (g) Atomic mass Electrical charge (C) Relative

KATRIN_1 [288]

Answer:

explaination:

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8 0

3 years ago

Las capas del lecho marino del Mar Mediterráneo cuentan la historia de los cambios ambientales en el hoy desértico norte de Afri

slamgirl [31]

Answer:

160.000 años corresponde a 16.000 décadas.

Explanation:

Para resolver correctamente el ejercicio debemos plantear la regla de tres simple de la siguiente manera:

1 década equivale a 10 años; A cuantas decadas equivalen 160.000 años?

1 década→10 años

x ←160.000 años

Debemos multiplicar 160.000 por 1 y luego dividir entre 10 ;

x=( $\frac{160.000x1}{10}$ )=16.000 décadas; en notación científica sería 16x10^3.

Respuesta: 160.000 años corresponde a 16.000 décadas.

5 0

3 years ago

Calculate q (in units of joules) when 1.850 g of water is heated from 22 °C to 33 °C

lisov135 [29]

The answer is 7345 g

5 0

3 years ago

Which statement is true about oxidation and reduction in an electrochemical cell?

Mila [183]

Answer : The correct option is, (3) Oxidation occurs at the anode and reduction occurs at the cathode.

Explanation :

Electrochemical cell : It is a type of device which is used to convert the chemical energy into electrical energy during the redox reaction.

In the electrochemical cell, there are two electrodes. The electrode on which the oxidation takes place is called the anode (or negative pole) and the electrode on which the reduction takes place is called the cathode (or positive pole). This cell is connected by the salt bridge.

In the external circuit, the electrons flow from the anode (negative pole) to cathode (positive pole) through the voltmeter.

In the inner circuit, the ions flow through the salt bridge.

Hence, the correct option is, (3) Oxidation occurs at the anode and reduction occurs at the cathode.

7 0

3 years ago

Read 2 more answers

A 4.00L flask containing Ne at 25 C and 6.00 atm is joined by a valve to an 8.00 L flask Ar at 25 C and 2.00 atm.

timama [110]

Answer:

$P=3.33atm$

Explanation:

Hello!

In this case, since know the volume, temperature and pressure of the initial containers, we can compute the moles of each gas prior to the opening of the valve as shown below:

$n_{Ne}=\frac{6atm*4L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.981molNe\\\\n_{Ar}=\frac{2atm*8L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.654molAr$

Next, we add them up to obtain the total moles:

$n_T=0.981mol+0.654mol=1.635mol$

Now, the total volume:

$V_T=4.00L+8.00L=12.00L$

Finally, the total pressure is computed by using the ideal gas equation:

$P=\frac{1.635mol*0.08206\frac{atm*L}{mol*K}*298.15K}{12.00L}\\\\P=3.33atm$

Best regards!

6 0

3 years ago