Question

Determine the empirical formula for c6n4o10

Answer 1

Let us derive empirical formula

Explanation:

We are given with compound C₆N₄O₁₀: mass percentage of all is :

For C = 12 x 6 /288=0.25%

For N= 14 x 4 /288=0.19%

For 0= 16 x 10/288=0.5%

The elements present are :

         Atomic mass   moles                       Simplest ratio           rounding off

C      12                        0.25/12=0.020             0.02/0.02=1           2

N       14                       0.9/14=0.06                    0.06/0.02=3         6

O       16                        0.5/16=0.03                   0.03/0.02=1.5       3

The empirical formula derived is : C₂n₆O₃