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3 years ago

Determine the empirical formula for c6n4o10

Chemistry

1 answer:

ANEK [815]3 years ago

7 0

<h2>Let us derive empirical formula </h2>

Explanation:

We are given with compound C₆N₄O₁₀: mass percentage of all is :

For C = 12 x 6 /288=0.25%

For N= 14 x 4 /288=0.19%

For 0= 16 x 10/288=0.5%

The elements present are :

Atomic mass moles Simplest ratio rounding off

C 12 0.25/12=0.020 0.02/0.02=1 2

N 14 0.9/14=0.06 0.06/0.02=3 6

O 16 0.5/16=0.03 0.03/0.02=1.5 3

The empirical formula derived is : C₂n₆O₃

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Answer:

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3 years ago

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3 years ago

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Answer:

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Explanation:

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3 years ago

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neonofarm [45]

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Read 2 more answers

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Answer:

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3 years ago