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3 years ago

Determine the empirical formula for c6n4o10

Chemistry

1 answer:

ANEK [815]3 years ago

7 0

<h2>Let us derive empirical formula </h2>

Explanation:

We are given with compound C₆N₄O₁₀: mass percentage of all is :

For C = 12 x 6 /288=0.25%

For N= 14 x 4 /288=0.19%

For 0= 16 x 10/288=0.5%

The elements present are :

Atomic mass moles Simplest ratio rounding off

C 12 0.25/12=0.020 0.02/0.02=1 2

N 14 0.9/14=0.06 0.06/0.02=3 6

O 16 0.5/16=0.03 0.03/0.02=1.5 3

The empirical formula derived is : C₂n₆O₃

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His strict imposition of autocratic rule was supported by his appointment by the King, who otherwise was not directly involved.

Explanation:

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3 years ago

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Sighting along the C2-C3 bond of 2-methylbutane, the least stable conformation (Newman projection) has a total energy strain of

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Answer:

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Explanation:

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Additionally, we have several energy values for each interaction present in the Newman structures:

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Now, we can calculate the energy for each molecule.

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Molecule B

In this molecule, we have a Methyl-methyl eclipse interaction a Methyl-H eclipse interaction and an H-H eclipse interaction, so:

(11)+(6)+(4) = 21 KJ/mol

Molecule C

In this molecule, we have 1 Methyl-methyl gauche interaction only, so:

3.8 KJ/mol

Molecule D

In this molecule, we have three Methyl-H eclipse interaction, so:

(6*3) = 18 KJ/mol

Molecule E

In this molecule, we have 1 Methyl-methyl gauche interaction only, so:

3.8 KJ/mol

Molecule F

In this molecule, we have a Methyl-methyl eclipse interaction a Methyl-H eclipse interaction and an H-H eclipse interaction, so:

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The structures with higher energies would be less stable. In this case, structures B and F with an energy value of 21 KJ/mol (see figure 2).

I hope it helps!

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